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Shell Programming and Scripting

Extract string between two delimiter

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# 1  
Old 08-12-2013
Extract string between two delimiter
I want a string between two delimeter like ( ) from file.

Input File,
Code:
2007_08_07_IA-0100-014_(January).PDF 
2007_08_07_IA-0100-031_(January February March
April June July).PDF 
2008-02-28_KR-1022-003_(January
febuary
march 
april
may).CSV

Output File,
Code:
January
January February March April june july
January February March April May

Can somebody help me with the above situation,
Last edited by Scott; 08-12-2013 at 11:38 AM.. Reason: Please use code tags for code and data
# 2  
Old 08-12-2013
Are these file names in different lines? or in a single line?

--ahamed
# 3  
Old 08-12-2013
Try
Code:
awk '{while (!($0~/\.... *$/)) {getline x;$0=$0" "x}}{gsub (/^[^(]*\(|\).*$/,"")}1' file
January
January February March April June July
January febuary march  april may

# 4  
Old 08-12-2013
Another approach:
Code:
awk '{v=$0;gsub(/.*\(|\).*/,x,v);s=s?s OFS v:v}/\./{print s;s=""}' file

This User Gave Thanks to Yoda For This Post:
RavinderSingh13
# 5  
Old 08-13-2013
Quote:
Originally Posted by ahamed101
Are these file names in different lines? or in a single line?

--ahamed
yes this file names in different lines.
# 6  
Old 08-13-2013
Quote:
Posted by Yoda:
Another approach:


Code:
awk '{v=$0;gsub(/.*\(|\).*/,x,v);s=s?s OFS v:v}/\./{print s;s=""}' file
Hello Yoda,

Could you please explain this code, I will be grateful to you.




Thanks,
R. Singh
# 7  
Old 08-13-2013
Quote:
Originally Posted by RudiC
Try
Code:
awk '{while (!($0~/\.... *$/)) {getline x;$0=$0" "x}}{gsub (/^[^(]*\(|\).*$/,"")}1' file
January
January February March April June July
January febuary march  april may

Thank you. I need one more help, I have another file with just delimeter change( ) to " ".
so in this code where i have to change?
Last edited by Pratik Majithia; 08-13-2013 at 03:18 AM..
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