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how to cut all string after the last delimiter?


 
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# 1  
Old 02-28-2012
how to cut all string after the last delimiter?

hi all,

suppose a string:

Code:
abc/def/ghi/jkl/mn.txt

and i want to get the file name without the path.

however, different files have different paths, therefore the number of delimiter is uncertain.

thanks so much!
# 2  
Old 02-28-2012
What about something like?

Code:
$ echo "abc/def/gh/joe.txt" | awk -F"/" '{print $NF}'
joe.txt

These 2 Users Gave Thanks to joeyg For This Post:
# 3  
Old 02-28-2012
Try using basename <full_path_to_file>

$ basename /sndc002/app/appsndc/sndcappl/admin/sndc01.txt
sndc01.txt
This User Gave Thanks to bab@faa For This Post:
# 4  
Old 02-28-2012
If you are doing this within a loop, you may want to consider using the built-in feature of bash/ksh parameter expansion. This will save you 1 exec for every loop
Code:
v="abc/def/ghi/jkl/mn.txt"
echo ${v##*/}

This User Gave Thanks to chihung For This Post:

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