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Top Forums Programming Newline in ANSI-C standard functions Post 303020110 by yifangt on Friday 13th of July 2018 01:13:10 PM
Old 07-13-2018
unclear with memset() with strcpy()/strncpy()

Thank you so much for your patience with my basics still, as I feel getting better to understand more.
strncpy doesn't want the size of the origin string: It wants the size of the destination buffer. ...... If you'd used strcpy, you would have been safe.
To see how things are working in the memory in order to understand those garbage left, I got error in the Block Two of following code:***buffer overflow detected ***: ./memset01 terminated
Code:
#include <stdio.h>
#include <string.h>

//More about that some said don't use strcpy() but use strncpy()!!!
int main () {
   char str1[128];
   char str2[256];
   int len1, len2;
   len1=strlen("this is string1");
   len2=strlen("That is test string2");
   printf("Length of str1[128]: %d\n", len1);
   printf("Length of str2[256]: %d\n\n", len2);

   strcpy(str1, "this is string1");
   strcpy(str2, "That is test string2");

   printf("Length of strlen(str1): %lu\n", strlen(str1));
   printf("Length of strlen(str2): %lu\n\n", strlen(str2));

/*Start of block One***********************/
   memset(str1, 'X', strlen(str1)+113); // fills the first 128 bytes of the memory area pointed to by str1 with the constant byte 'X'.
   memset(str2, 'X', strlen(str2)+108); // fills the first 128 bytes of the memory area pointed to by str2 with the constant byte 'X'.

   strncpy(str1, "this is string1", len1);
   strncpy(str2, "That is test string2", len2);
   puts("___Line 1___:");
   puts(str1);
   puts("___Line 2___:");
   puts(str2);
   printf("------------------------------------------------------------------\n");
/*End of block One***********************/

/*Start of block Two***********************/
   memset(str1, 'X', strlen(str1)+113); //fills the first 128 bytes of the memory area pointed to by str1 with the constant byte 'X'.
   memset(str2, 'X', strlen(str2)+108); //fills the first 128 bytes of the memory area pointed to by str2 with the constant byte 'X'.
   strcpy(str1, "this is string1");
   strcpy(str2, "That is test string2");

   puts("___Line 1___:");
   puts(str1);
   puts("___Line 2___:");
   puts(str2);
   printf("------------------------------------------------------------------\n");
/*End of block Two***********************/
   return(0);
}

If I switch the two blocks, there is no buffer overflow for the memset().
What is going on in the memory? Thanks!

Last edited by yifangt; 07-16-2018 at 12:00 PM.. Reason: typos
 

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streqvcmp(3)							Programmer's Manual						      streqvcmp(3)

NAME
streqvcmp - compare two strings with an equivalence mapping SYNOPSIS
#include <your-opts.h> cc [...] -o outfile infile.c -lopts [...] int streqvcmp(char const* str1, char const* str2); DESCRIPTION
Using a character mapping, two strings are compared for "equivalence". Each input character is mapped to a comparison character and the mapped-to characters are compared for the two NUL terminated input strings. This function name is mapped to option_streqvcmp so as to not conflict with the POSIX name space. str1 first string str2 second string RETURN VALUE
the difference between two differing characters ERRORS
none checked. Caller responsible for seg faults. SEE ALSO
The info documentation for the -lopts library. ao_string_tokenize(3), configFileLoad(3), optionFileLoad(3), optionFindNextValue(3), optionFindValue(3), optionFree(3), optionGetValue(3), optionLoadLine(3), optionMemberList(3), optionNextValue(3), optionOnlyUsage(3), optionProcess(3), optionRestore(3), optionSaveFile(3), optionSaveState(3), optionUnloadNested(3), optionVersion(3), strequate(3), streqvmap(3), strneqvcmp(3), strtransform(3), 2014-06-10 streqvcmp(3)
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