I found my logic mistake and changed as below yesterday (divide result from 1min CPU LOAD with 5mins and 15mins, if it is less than 1.03 (3%) then it is normal, if more than 1.03 (3) then is warning, if more than 1.05 (5%) it is critical.).
1 min load 3% < 5mins and 15mins is normal
1 min load 3% > 5mins or 15mins is warning
1 min load 5% > 5mins or 15mins is critical
Code:
#!/bin/ksh
str1=`uptime | awk '{print $10}'| sed 's/,//'`
str2=`uptime | awk '{print $11}'| sed 's/,//'`
str3=`uptime | awk '{print $12}'| sed 's/,//'`
warn_level=$(( 1.03 ))
crit_level=$(( 1.05 ))
if [[ $str1/$str2 -gt $crit_level || $str1/$str3 -gt $crit_level ]]; then
status=2
statustxt="CPU load is critical - $str1"
elif [[ $str1/$str2 -gt $warn_level || $str1/$str3 -gt $warn_level ]]; then
status=1
statustxt="CPU load is Warning - $str1"
else
status=0
statustxt="CPU load is normal, no spike - $str1"
fi
echo "$status CPULOAD_spike PERFDATA=$str1 $statustxt"
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15
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hi there again,
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col1 col2 col3
val1 val2 val1/val2
valn valm valn/valm
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Hi experts,
I'm facing trouble with the below bash script, any help is appreciated
#!/usr/bin/bash
..
if (( "${date1}" > "${l_date1}" ))
then
echo "success"
else
echo "nothing"
fi
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Hello.
LEAP_VERSION="4.2"
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Hi guys...
I am working on limited basic set of maths routines for ksh93 that can be sourced as . ./ksh_math.sh and I am gobsmacked by its capabilities.
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06-29-2016
