QUESTION: How can I cut out the date from just the first line and reformat it to 31-Jul-2007? I'll restate the question at the bottom again...
DESCRIPTION: I need to cut a date out of a file - an example of the date's format in the file is 2007-07-31. It's in the 5th field and is separated... (1 Reply)
Hi All,
How can i use the cut option to only output the number of rows, which is 2 is this case ? Pls note that the number of digit before the delimiter ":" is always varying.
$ grep -n uuu xxx
2:** xxx yyy gg 44 tt uuu 2007
$ (2 Replies)
Hi,
I've a situation where,
a=xxx.yyy.zzz.txt
EXTN=`echo $a | cut -d . -f2`
Using the above code it delimites and will return "yyy.zzz.txt" to EXTN. But i need to get only the extension "txt". so as per the above code it delimits in the first "." itself. Can anyone help how to do... (6 Replies)
Is there a way to use a word as a delimiter with cut? Or is there a way to use sed or awk with a word as a delimiter? I don't care which program I use for a delimiter I just want to use a word as a delimiter. (2 Replies)
I need to cut or otherwise get the 4th and 5th position output of
for i in `date +%H` ; do vnstat --dumpdb | grep "h;$i" ; done
example output is:
h;13;1310318701;443;93
I only need ";443;93" from any given run of "for i in `date +%H` ; do vnstat --dumpdb | grep "h;$i" ; done"
Thanks... (3 Replies)
HI,
I have a file like below
"103865","103835","Zming","","Zhu","103965","Sunnyvale","US",
"116228","116227","Morlla","","Kowalski","113228","Paese "(Treviso)""IT"
I want to validate the 7th column which is below.
"Sunnyvale"
"Paese
In the above 7th column Paese is not ended with... (9 Replies)
hi all,
suppose a string:
abc/def/ghi/jkl/mn.txt
and i want to get the file name without the path.
however, different files have different paths, therefore the number of delimiter is uncertain.
thanks so much! (3 Replies)
Hi all,
I have a number of strings like below:
//mnt/autocor/43°13'(33")W/
and i'm trying to get the numbers in this string, for example
431333
please help
thanks ahead (14 Replies)
i have list of names in a text file and I wanted to delete the commas en every line.
for example: inside the text is a list of names in it with commas after each line. I wanted to delete these commas. which command must I execute for this?
unix,
dale,
shawn,
aaron, (4 Replies)
Discussion started by: garfish
4 Replies
LEARN ABOUT DEBIAN
bzexe
BZEXE(1) General Commands Manual BZEXE(1)NAME
bzexe - compress executable files in place
SYNOPSIS
bzexe [ name ... ]
DESCRIPTION
The bzexe utility allows you to compress executables in place and have them automatically uncompress and execute when you run them (at a
penalty in performance). For example if you execute ``bzexe /bin/cat'' it will create the following two files:
-r-xr-xr-x 1 root bin 9644 Feb 11 11:16 /bin/cat
-r-xr-xr-x 1 bin bin 24576 Nov 23 13:21 /bin/cat~
/bin/cat~ is the original file and /bin/cat is the self-uncompressing executable file. You can remove /bin/cat~ once you are sure that
/bin/cat works properly.
This utility is most useful on systems with very small disks.
OPTIONS -d Decompress the given executables instead of compressing them.
SEE ALSO bzip2(1), znew(1), zmore(1), zcmp(1), zforce(1)CAVEATS
The compressed executable is a shell script. This may create some security holes. In particular, the compressed executable relies on the
PATH environment variable to find gzip and some other utilities (tail, chmod, ln, sleep).
BUGS
bzexe attempts to retain the original file attributes on the compressed executable, but you may have to fix them manually in some cases,
using chmod or chown.
BZEXE(1)