Hi,
I have this script:
awk -v va=45 '$0~va{print}' flo2
That returns: "4526745 1234 " (this is the only line of the file "flo2".
However, I would like to get "va" to match the begining of the line, so that is "va" is different than 45 (eg. 67, 12 ...) I would not have any output. That... (3 Replies)
I'm trying to math all class references in a C++ file using grep with regular expression. I'm trying to know if a specific include is usuless or not, so I have to know if there is a refence in cpp.
I wrote this RE that searches for a reference from class ABCZ, but unfortunately it isn't working... (0 Replies)
Hi all,
How am I read a file, find the match regular expression and overwrite to the same files.
open DESTINATION_FILE, "<tmptravl.dat" or die "tmptravl.dat";
open NEW_DESTINATION_FILE, ">new_tmptravl.dat" or die "new_tmptravl.dat";
while (<DESTINATION_FILE>)
{
# print... (1 Reply)
Readers,
Reading a previous post about comparing files using awk ('awk-compare-2-columns-2-files-output-whole-line', https://www.unix.com/shell-programming-scripting/168432-awk-compare-2-columns-2-files-output-whole-line.html), it is possible to adjust this, so that regular expression can be used... (8 Replies)
Hello All,
I'm trying to extract the lines between two consecutive elements of an array from a file.
My array looks like:
problem_arr=(PRS111 PRS213 PRS234)
j=0
while } ]
do
k=`expr $j + 1`
sed -n "/${problem_arr}/,/${problem_arr}/p" problemid.txt
---some operation goes... (11 Replies)
Hi all
I have a list of file names in array. But this file names are not exact. so i want to search whether a file exists or not using regular expression.
code snippet:
if ;
then
echo "File exists"
else
echo "File does not exits"
fi
over here "*EQST*" should be treated as a regular... (4 Replies)
Hi Gurus,
I need to identify the file with below format:
ABC20110101.DAT
ABCD2011010103.DAT
If I use ABC*\.DAT, it get two file. I want to get file after "ABC' then number, the ".DAT".
I tried
ABC* but it doesn't work.
Thanks in advance. (9 Replies)
Hello Everyone,
I have a file sam1 with the below content
SYSYSID;MANDT;/SIE/AD_Z0M_INDX;/SIE/AD_Z0M_KEY1
echo $Regex
\bSYSYSID\b|\bMANDT\b|\b/SIE/AD_Z0M_INDX\b|\b/SIE/AD_Z0M_KEY1\b
cat sam1 | grep -Eo $Regex
I expect the result as
SYSYSID
MANDT
/SIE/AD_Z0M_INDX
/SIE/AD_Z0M_KEY1... (4 Replies)
#!/bin/sh
Today=date '+%Y%m%d'
for file in `ls *.csv *txt`
do
echo "Start woprking with ${file}"
if ; then
do something
elif ; then
do something
else
echo "Unkniowned file name"
... (6 Replies)
Discussion started by: digioleg54
6 Replies
LEARN ABOUT BSD
regex
REGEX(3) Library Functions Manual REGEX(3)NAME
re_comp, re_exec - regular expression handler
SYNOPSIS
char *re_comp(s)
char *s;
re_exec(s)
char *s;
DESCRIPTION
Re_comp compiles a string into an internal form suitable for pattern matching. Re_exec checks the argument string against the last string
passed to re_comp.
Re_comp returns 0 if the string s was compiled successfully; otherwise a string containing an error message is returned. If re_comp is
passed 0 or a null string, it returns without changing the currently compiled regular expression.
Re_exec returns 1 if the string s matches the last compiled regular expression, 0 if the string s failed to match the last compiled regular
expression, and -1 if the compiled regular expression was invalid (indicating an internal error).
The strings passed to both re_comp and re_exec may have trailing or embedded newline characters; they are terminated by nulls. The regular
expressions recognized are described in the manual entry for ed(1), given the above difference.
SEE ALSO ed(1), ex(1), egrep(1), fgrep(1), grep(1)DIAGNOSTICS
Re_exec returns -1 for an internal error.
Re_comp returns one of the following strings if an error occurs:
No previous regular expression,
Regular expression too long,
unmatched (,
missing ],
too many () pairs,
unmatched ).
3rd Berkeley Distribution May 15, 1985 REGEX(3)