Here is the code I'm using
{
printf("%11d %4.2f\% %4.2f\%\n", $1,$2,$3);
}
I want the output to look something like
1235415234 12.24% 52.46%
Instead it looks something like
319203842 42.27\%4.2f\%
How do I just print a "%" without awk or printf thinking I'm trying to do... (1 Reply)
I am trying to use printf with a character string that is used within a do loop. The problem is that while in the loop, the printf prints the variable name instead of the value. The do loop calls the variable name from a text file (called device.txt):
while read device
do
cat $device.clean... (2 Replies)
Hi I'm having a problem with converting a file:
ID X
1 7
1 8
1 3
2 5
2 7
2 2
To something like this:
ID X1 X2 X3
1 7 8 3
2 5 7 2
I've tried the following loop:
for i in `cat tst.csv| awk -F "," '{print $1}'| uniq`;do grep -h $i... (4 Replies)
Hi Friends,
I am trying to insert lines of the below format in a file:
# x3a4914 Joe 2010/04/07
# seh Lane 2010/04/07
# IN01379 Larry 2010/04/07
I am formatting the strings as follows using awk printf:
awk 'printf "# %s %9s %18s\n", $2,$3,$4}'
... (2 Replies)
hallow all i need your advice about this script
i have script like this:
INDEX=/zpool1/NFS/INDEX/${1}
SCRIPT=/zpool1/NFS/script/${1}
LIST=SAMPLE
cd ${SCRIPT}
for i in `cat ${LIST}`
do
GETDATE=`echo ${i}|awk '{print substr($1,9,8)}'`
/usr/xpg4/bin/awk -F ":" '{close(f);f=$4}{print >>... (4 Replies)
Hi,
Struggling with single quotes, double quotes, etc.
I want to print a header line, followed by lines with actual values, based on a print option.
In real life it is going to be something like 15 print options and 50 values.
Output will be 1 header and several value lines.
In this example... (5 Replies)
Is possible to print padded string in printf?
Example
echo 1 | awk '{printf("%03d\n", $1)}'
001I want
S1
S11
S2
S21to be padded as:
S01
S11
S02
S21Thanks! (26 Replies)