09-08-2009
Parse a line which has different word length
Hi All,
Please let me know a command to parse the below line and find the words,
I have a line like this
40609 39930
In this above line the two words are separted by space.The length of this two words may differ.
I want to put 40609 in var_one and 39930 in var_two.
Eg.
Input line is
40609 39930
echo $var_one
echo $var_two
(some command which should give the below ouput)
40609
39930
Thanks in advance,
Giri.
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LEARN ABOUT DEBIAN
polish
POLISH(5) Debian POLISH(5)
NAME
polish - a list of Polish words
DESCRIPTION
/usr/share/dict/polish is an ASCII file which contains an alphabetic list of words, one per line.
FILES
/etc/dictionaries-common/words is a symbolic link to a /usr/share/dict/<language> file. /usr/share/dict/words is a symbolic link to
/etc/dictionaries-common/words, and is the name by which other software should refer to the system word list. See
select-default-wordlist(8) for more information.
The directory /usr/share/dict can contain word lists for many languages, with name of the language in English, e.g., /usr/share/dict/french
and /usr/share/dict/danish contain respectively lists of French and Danish words if they exist. Such lists should be coded using the UTF-8
character set encoding.
SEE ALSO
ispell(1), select-default-wordlist(8), and the Filesystem Hierarchy Standard.
HISTORY
The words lists are not specific, and may be generated from any number of sources.
The system word list used to be /usr/dict/words. For compatibility, software should check that location if /usr/share/dict/words does not
exist.
AUTHOR
Word lists are collected and maintained by various authors.
Debian Project March 29th, 2011 POLISH(5)