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what is wrong in this awk or grep ....

 
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# 1  
Old 11-14-2007
what is wrong in this awk or grep ....
hi champs,

i have a strange problem,
let ,
i have a array1, whose 1st character is ${array1[0]}=h

let i want to search test.txt by awk/grep where the 1st character is the ${array1[0]}....

if i am seraching by awk/grep by using variable..it return no rows from test.txt...
awk -v find=${array1[0]} '/^find.*/ {print $0}' test.txt
grep '^${array1[0]}.*' test.txt

but if i am doing it by following methods, strangely it gives me the xact o/p
grep '^h.*' test.txt
awk '/^h.*/ {print $0}' test.txt

any suggesttion , how to make my search dynamic.....or what is the problem in above awk/grep
# 2  
Old 11-14-2007
in grep, "^$" denotes the begaining and end of search string. whereas "^h.*" means any name start with "h". You could better understand if you use "grep '^$h.*' test.txt"
# 3  
Old 11-15-2007
thankx a lot...but even if i tried this one...
grep '^\${array1[0]}.*' test.txt=> no use
but what is the problem in awk.......
awk -v find=${array1[0]} '/^find.*/ {print $0}' test.txt
any suggestions.....
 
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