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Delete all lines without a trailing semi colon


 
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# 1  
Old 05-23-2018
Delete all lines without a trailing semi colon

shell : bash
os : RHEL 7.2

I have a file like below

Code:
61265388
1-11Y5C-7690
1-11Y4Q-6763
INSERT INTO emp VALUES('oramds:test.xref','CBS_01','MIGWO161265388','61265388','N',SYSDATE);

INSERT INTO emp VALUES('oramds:test.xref','COMMON','MIGWO161265388','MIG1COMMON61265388','N',SYSDATE);
INSERT INTO emp VALUES('oramds:test.xref','SEBL_01','MIGWO161265388','1-11Y5C-7690','N',SYSDATE);

I want to remove all lines (including blank lines) without a trailing semi colon. Any idea how I could do this preferably in sed/awk ?

expected output

Code:
INSERT INTO emp VALUES('oramds:test.xref','CBS_01','MIGWO161265388','61265388','N',SYSDATE);
INSERT INTO emp VALUES('oramds:test.xref','COMMON','MIGWO161265388','MIG1COMMON61265388','N',SYSDATE);
INSERT INTO emp VALUES('oramds:test.xref','SEBL_01','MIGWO161265388','1-11Y5C-7690','N',SYSDATE);

# 2  
Old 05-23-2018
Any attempts / ideas / thoughts from your side?
# 3  
Old 05-23-2018
Assuming your input is in a file called file.txt:
Code:
sed -n '/;$/p' file.txt

Or with grep:
Code:
grep  ';$' file.txt

Andrew
This User Gave Thanks to apmcd47 For This Post:
# 4  
Old 05-23-2018
Or:
Code:
awk '/;$/' file

or
Code:
sed '/;$/!d' file

This User Gave Thanks to RudiC For This Post:

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