Scan of log file in Linux for entries in last 15 minutes for matching a pattern

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# 1  
Old 03-05-2014
Code Scan of log file in Linux for entries in last 15 minutes for matching a pattern

Is there any way I can do scan of log file in Linux, where the log file entries for last 15 minutes can be searched for a particular pattern.

The log file entries are in below format.

2014-01-27T23:08:53.924-0500 LDAP authentication error
2014-01-27T23:08:53.934-0500 LDAP authentication error

My intention is to send an email alert if there is any entry in this file for the pattern in last 15 minutes.

# 2  
Old 03-05-2014
Logic would be...

1. Get current time

2. subtract 15 minutes from time

3. Convert it to the same format as the log entry: YYYY-01-27 and HH:MM.SS.ddd (you only need the HH:MM)

date --date-string="- 15 minutes"....depends on o/s...this works on bash


date  +%Y-%M-%dT%H:%M --date="-15 minutes"

4. grep or awk the log file (using regular expression if need be)...

something to get you started

Last edited by blackrageous; 03-05-2014 at 06:40 PM..
# 3  
Old 03-05-2014

The pattern is as below.

LDAP authentication error: [LDAP: error code 49 - 80090308: LdapErr: DSID-0C0903AA

# 4  
Old 03-05-2014
See this link for doing it in awk...

Time Functions - The GNU Awk User's Guide
# 5  
Old 04-09-2014

From your replies i figured out this, but problem is that the command will not output anything if there is no entry for the particular minute, i.e 15 minutes before.
sed -n "/^$(date --date='15 minutes ago' '+%Y-%m-%dT%H:%M')/,\$p" $ERROR_LOG

Is there any way to fix this?

Thanks & regardsSmilie,
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