Shell Programming and Scripting

Hi all!!

Here is my question: very simple i know, but i'm absolutely nul with awk:
how can you get any thing between two patterns: here's what my file likes like:

PATTERN some text
some more text
other text


PATTERN some more text

My concer is to get all text between the 2 PATTERN, knowing that the "some text" and "some more text" is not the same? ANd that i need all from the PATTERN upto the line before the next PATTERN line?

Thanx

Jason

/PATTERN some text/,/PATTERN some more text/ {
....do whatever.....
}

Take alook at the Awk builtin variables, specifically RS (Record Separator). You can use these in the begin statement

Code:

awk BEGIN {
     RS="PATTERN THAT SEPARATES EACH RECORD"
}
     
{Begin Record Parse}
     
END {
      Do Something Before Closing the program
}

let me be more explicit:

my file looks like this:

M U S E E some text
text
more text
some more text


M U S E E
different text
and some more different text

What i want to do is to split the original file, according to the number of "M U S E E" found in it..
The number of lines between each "M U S E E" varies...

Please help... i'm drowning..

Jason

if your records are separated by empty lines, you can RS=""

Code:

BEGIN {
   RS=""
}
$1=$1

ok, now, how do you extract each M U S E E block of text, and put that in a file?

nawk -f penguin.awk penguin.txt > extractedPenguin.txt

penguin.awk:

Code:

BEGIN {
   RS=""
}
$1=$1 { if $1 ~ /^M U S E E/ { print $0 }