awk question

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# 1  
Old 11-06-2001
Question awk question

I have the following error:

ls -lt | awk 'BEGIN NR > 1 { print $2, $9 }'
Syntax Error The source line is 1.
The error context is
BEGIN >>> NR <<< > 1 { print $2, $9 }
awk: 0602-500 Quitting The source line is 1.

What I want to do is ls a directory, skip the first line, then $2 will determine if the file is linked and $9 is the file name. I want to be able to say if $2 is less than or equal to 1 then compress $9. Any help would be appreciated.
# 2  
Old 11-06-2001
ls -lt | awk 'NR>1 {print $2, $9}'
# 3  
Old 11-06-2001
that works well

The command you gave me works well. Now I want to take the output and perform some logic on it. This is what I wrote:

ls -lt | awk 'NR>1 {print $2, $9}'
if [ $2 <= $9 ]
compress $9
return 0

Unfortunately it is not working.
# 4  
Old 11-06-2001
I think I am getting closer

ls -lt | awk 'NR>1, $2 <= 1 {compress $9}'
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