Shell Programming and Scripting

Hi, I'm using a while-loop in an awk script. If it matches a regular expression, it prints a line. Unfortunately, each line that is printed in this loop is followed by an extra character, "1".

While-statement extracted from my script:

Code:

getline temp;
while (temp ~ /.* x[0-9][0-9][0-9][0-9] .*/) print temp getline temp;

Sample text from original text file:

Code:

x01334
x01432
t-4321

Outputted text:

Code:

x013341
x014321

Does anyone know why this is happening? Any help would be appreciated, thanks

Hi,

What is the context of that piece of code?

I think you are sending to print two parts:
'temp' -> which has the line
'getline temp' -> which returns success (the number 1).

and the 'print' function joins them and send it to output.

Regards,
Birei

Continuing the observation by birei, all you should need to do is to add a semicolon and some curly braces.

Messy

Code:

while (temp ~ /.* x[0-9][0-9][0-9][0-9] .*/){ print temp;  getline temp; }

Better

Code:

while (temp ~ /.* x[0-9][0-9][0-9][0-9] .*/) 
{
   print temp;
   getline temp;
}

Thank-you Agama and Birei, you two are correct