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Full Discussion: [SOLVED] Permission Denied
Top Forums UNIX for Dummies Questions & Answers [SOLVED] Permission Denied Post 302850447 by gacanepa on Wednesday 4th of September 2013 07:59:40 PM
Old 09-04-2013
Quote:
Originally Posted by parpaa
Folder permission: drwxr-xr-x

You might be right, this might be different issue-

The piece of code is something like this
Code:
        if [[ "${date1}" > "${date2}" ]] 

        then
        echo "file movement";

        sftp sftpabc@abc.com  <<EOF
        cd folder
        put ${file1}
        EOF
        echo "${file1},$USER,$DATE" >> log1.txt
else
echo "do nothing"
fi

This may be a long shot but the closing EOF must not be indented.
Another suggestion. Try placing set -x at the beginning of your script for debugging purposes. Next time you run the script, each step will be shown in the screen as the script executes, and that may give you a better idea as to what's wrong.
If you don't get your head around to it with these suggestions and the others that have been given in this thread, please copy here your full script and a concise explanation of what it's supposed to accomplish.
 

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SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
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