05-22-2013
Recursively search the string from a column in no. of files
i have a file named keyword.csv(contains around 8k records) which contains a no. of columns.
The 5th column contains all the keywords.
I want to recursively search these keywords in all .pl files(around 1k) and display the filename....Afterthat i will use the filename and some of the column from the keyword.csv to update the database.
I am using below code...but it is not working as keyword.csv contains a no of columns...
find . -type f -name "*.pl" | xargs fgrep -f keyword.csv
Could you please let me know how to handle it.
Thank you in advance.
Last edited by millan; 05-22-2013 at 08:23 AM..
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LEARN ABOUT FREEBSD
apropos
APROPOS(1) BSD General Commands Manual APROPOS(1)
NAME
apropos, whatis -- keyword search whatis documentation databases
SYNOPSIS
apropos [-d] keyword ...
whatis [-d] keyword ...
DESCRIPTION
The apropos utility searches a set of databases looking for documentation matching each keyword and displays the results. The whatis utility
does the same search but only on complete words.
-d Print extra debugging information.
The keyword is simply passed to grep(1) allowing for extended regular expression matches.
ENVIRONMENT
The following environment variables affect the execution of apropos:
MANLOCALES, MANPATH, PATH
Used to find the location of the whatis database files. See manpath(1) for additional information.
PAGER Program used to display files. If unset, more -s is used.
DIAGNOSTICS
The apropos utility exits 0 if a keyword matched and 1 if no keywords are matched or no whatis databases are found.
SEE ALSO
grep(1), makewhatis(1), man(1), manpath(1), man.conf(5)
BSD
September 1, 2010 BSD