In HP-UX the date command does not have the "-d" switch like some other *nixes do. I'm working a simple script to tell me, given the day, month and year what day of the week that falls on.
Assuming valid day, month and year input (I'd perform quality checks on the input separately, but not shown here), would the following work for all dates? Or are there some corner cases that may not work correctly? I'm not worried about corner cases like way back in the 1500's when the Gregorian calendar 1st came online and how that might be screwed up.
The output is the output from a call to the 'cal' utility, plus the full name of the day of the week so that the named day of the week can be easily verified.
Code:
#!/bin/sh
day=$1
mth=$2
yr=$3
cal $mth $yr
set -A _WKDY Saturday Sunday Monday Tuesday Wednesday Thursday Friday
print ${_WKDY[$(cal $mth $yr | awk -vDD=$day 'FNR==3 {print ((7-$NF)+DD)%7}')]}
in awk,
Code:
FNR==3
means I skip the headers and am only concerned with the first week of the 'cal' output.
Breaking the math down:
Code:
(7-$NF)
Is an offset to "normalize" partial weeks since the first week of a month may have less than 7 days in it.
Code:
((7-$NF)+DD)
The offset is added to the numerical day of the month (DD)
Code:
((7-$NF)+DD)%7
The offset plus DD is then modded by 7 giving the numerical day of the week, of which, 0 is defined as Saturday, and 1-6 is defined as Sunday through Friday by how I set up the array.
I'm basically just wondering if anyone can break this given a modern date and valid inputs. (no using February 30th! :-) ) I can't break it, but I've a nagging suspicion I'm missing something.
Hi ,
I am working at Unix system,using c lang.
I need c fun which return the day of the week .
For example :
0- Sunday.
1- Monday.
....
10x. (4 Replies)
I need o get yesterday's day of week but im not exactly sure. the actual name is what i want. I can do it with numbers but im not sure with words. (3 Replies)
How to find the Day of the Week of the given Date using perl?
If I have a date in YYY--MM-DD format, how to find the DOW? Based on that, I need to find the following sunday.
Pls help. (5 Replies)
Hi All,
I have date in string format 'YYYY-MM-DD'. I want to know day of the week for this date.
Example. For '2005-08-21' my script should return '0' or Sunday
For '2005-08-22' it should return '1' or Monday
I want piece of code for HP-UX korn shell.
Appreciate reply on this. (5 Replies)
Hi all, I am trying to get dow from cal using below script
#! /bin/bash
YEAR=`echo $1 | cut -c 1-4`
MONTH=`echo $1 | cut -c 5-6`
DAY=`echo $1 | cut -c 7-8`
for i in 1 2 3 4 5 6 7
do
dayofweek=`cal $MONTH $YEAR | awk '$i == $DAY {printf("%s","$i")}'`
echo $dayofweek... (4 Replies)
I have been volunteered by my boss to be the sysadmin for our production redhat server. He asked me to tighten the security to avoid mishaps like "rm -f *" that occured not long ago.
Right now, we have 53 users sudo-ing into the machine and it is an audit nightmare. I am wondering if it... (15 Replies)
Hi everyone,
I have a shell script that merges many files down in to one, then removes unwanted lines, that part is working fine:
#!/bin/bash
FILES=/home/pi/temp/qbd/*
for f in $FILES
do
echo "Processing $f file..."
# take action on each file. $f store current file name
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Hi All,
I have the below requirement ,
if i give the week number for ex 41 i need to get the date for Monday and thursday for this given week. my expected output is 13/10/2014 (Monday's date) and 16/10/2014 (Thursday's date)
I am using GNU LINUX .
Pls help me with your thoughts.
Thanks in... (7 Replies)
Discussion started by: mohanalakshmi
7 Replies
LEARN ABOUT PHP
intlcalendar.getminimaldaysinfirstweek
INTLCALENDAR.GETMINIMALDAYSINFIRSTWEEK(3) 1 INTLCALENDAR.GETMINIMALDAYSINFIRSTWEEK(3)IntlCalendar::getMinimalDaysInFirstWeek - Get minimal number of days the first week in a year or month can have
Object oriented style
SYNOPSIS
public int IntlCalendar::getMinimalDaysInFirstWeek (void )
DESCRIPTION
Procedural style
int intlcal_get_minimal_days_in_first_week (IntlCalendar $cal)
Returns the smallest number of days the first week of a year or month must have in the new year or month. For instance, in the Gregorian
calendar, if this value is 1, then the first week of the year will necessarily include January 1st, while if this value is 7, then the week
with January 1st will be the first week of the year only if the day of the week for January 1st matches the day of the week returned by
IntlCalendar.getFirstDayOfWeek(3); otherwise it will be the previous years last week.
PARAMETERS
o $cal
- The IntlCalendar resource.
RETURN VALUES
An int representing a number of days or FALSE on failure.
EXAMPLES
Example #1
IntlCalendar.getMinimalDaysInFirstWeek(3)
<?php
ini_set('date.timezone', 'UTC');
ini_set('intl.default_locale', 'en_US');
$cal = new IntlGregorianCalendar(2013, 0 /* January */, 2);
var_dump(IntlDateFormatter::formatObject($cal, 'cccc')); // Wednesday
var_dump($cal->getMinimalDaysInFirstWeek(), // 1
$cal->getFirstDayofWeek()); // 1 (Sunday)
// Week 1 of 2013
var_dump(IntlDateFormatter::formatObject($cal, "'Week 'w' of 'Y"));
$cal->setMinimalDaysInFirstWeek(4);
// Still Week 1 of 2013 (1st week has 5 days in the new year)
var_dump(IntlDateFormatter::formatObject($cal, "'Week 'w' of 'Y"));
$cal->setMinimalDaysInFirstWeek(6);
// Week 53 of 2012
var_dump(IntlDateFormatter::formatObject($cal, "'Week 'w' of 'Y"));
The above example will output:
string(9) "Wednesday"
int(1)int(1)string(14) "Week 1 of 2013"
string(14) "Week 1 of 2013"
string(15) "Week 53 of 2012"
PHP Documentation Group INTLCALENDAR.GETMINIMALDAYSINFIRSTWEEK(3)
11-14-2012
