I want to grep a range of numbers in a log file. My log file looks like this:
20050807070609Z;blah blah
That is a combination of yr,month,date,hours,minutes,seconds.
I want to search in the log file events that happened between a particular time.
like between 20050807070000 to 20050822070000... (1 Reply)
I need to edit a list of numbers on the following form:
1 1.0
2 1.4
5 2.1
7 1.9
I want:
1 1.0
2 1.4
3 0.0
4 0.0
5 2.1
6 0.0
7 1.9
(i want to add the missing number in column 1 together with 0.0 in column 2).
I guess it is rather trivial but i didn't even manage to read column... (5 Replies)
Hi im new to unix and need to find a way to grep the top 5 numbers in a file and put them into another file. For example my file looks like this
abcdef 50000
abcdef 45000
abcdef 40000
abcdef 35000
abcdef 30000
abcdef 25000
abcdef 20000
abcdef 15000
abcdef 10000
and so on...
How can... (1 Reply)
Howdy experts,
We have some ranges of number which belongs to particual group as below.
GroupNo StartRange EndRange
Group0125 935300 935399
Group2006 935400 935476
937430 937459
Group0324 935477 935549
... (6 Replies)
Hello,
I have a column where there are values from 1 to 150.
I want to get the frequency of values in the following ranges:
1-5
6-10
11-15
....
....
....
146-150
How can I do this in a for loop?
Thanks,
Guss (1 Reply)
Dear Friends,
I want to know how to grep for the lines that has a number between given range(start and end).
I have tried the following sed command.
sed -n -e '/20030101011442/,/20030101035519/p'
However this requires both start and end to be part of the content being grepped. However... (4 Replies)
I am trying to extract specific information from a large *.sam file (it's originally 28Gb).
I want to extract all lines that are on chr3 somewhere in the range of 112,937,439-113,437,438.
Here is a sample line from my file so you can get a feel for what each line looks like:
seq.4 0 ... (8 Replies)
Hi,
I'm trying to match a filename that could be called anything from vout001 to vout252 and was trying to do a small test but I'm not getting the result I thought I would..
Can some one tell me what I'm doing wrong?
*****@********>echo $mynumber ... (4 Replies)
Hi
I am getting an argument which specifies the range of numbers. eg: 7-15
Is there a way that i can easily (avoiding loop) print the range of number between and including the specified above.
The above example should translate to 7,8,9,10,11,12,13,14,15 (3 Replies)
Discussion started by: tostay2003
3 Replies
LEARN ABOUT DEBIAN
bup-margin
bup-margin(1) General Commands Manual bup-margin(1)NAME
bup-margin - figure out your deduplication safety margin
SYNOPSIS
bup margin [options...]
DESCRIPTION
bup margin iterates through all objects in your bup repository, calculating the largest number of prefix bits shared between any two
entries. This number, n, identifies the longest subset of SHA-1 you could use and still encounter a collision between your object ids.
For example, one system that was tested had a collection of 11 million objects (70 GB), and bup margin returned 45. That means a 46-bit
hash would be sufficient to avoid all collisions among that set of objects; each object in that repository could be uniquely identified by
its first 46 bits.
The number of bits needed seems to increase by about 1 or 2 for every doubling of the number of objects. Since SHA-1 hashes have 160 bits,
that leaves 115 bits of margin. Of course, because SHA-1 hashes are essentially random, it's theoretically possible to use many more bits
with far fewer objects.
If you're paranoid about the possibility of SHA-1 collisions, you can monitor your repository by running bup margin occasionally to see if
you're getting dangerously close to 160 bits.
OPTIONS --predict
Guess the offset into each index file where a particular object will appear, and report the maximum deviation of the correct answer
from the guess. This is potentially useful for tuning an interpolation search algorithm.
--ignore-midx
don't use .midx files, use only .idx files. This is only really useful when used with --predict.
EXAMPLE
$ bup margin
Reading indexes: 100.00% (1612581/1612581), done.
40
40 matching prefix bits
1.94 bits per doubling
120 bits (61.86 doublings) remaining
4.19338e+18 times larger is possible
Everyone on earth could have 625878182 data sets
like yours, all in one repository, and we would
expect 1 object collision.
$ bup margin --predict
PackIdxList: using 1 index.
Reading indexes: 100.00% (1612581/1612581), done.
915 of 1612581 (0.057%)
SEE ALSO bup-midx(1), bup-save(1)BUP
Part of the bup(1) suite.
AUTHORS
Avery Pennarun <apenwarr@gmail.com>.
Bup unknown-bup-margin(1)