Match on a range of numbers

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# 1  
Old 12-11-2013
Match on a range of numbers

I'm trying to match a filename that could be called anything from vout001 to vout252 and was trying to do a small test but I'm not getting the result I thought I would..

Can some one tell me what I'm doing wrong?

*****@********[/home/aiw1]>echo $mynumber                                                         
*****@********[/home/aiw1]>if [ $mynumber == 'vout[0...252]' ]                                      
> then
> echo 't'
> else
> echo 'f'
> fi

# 2  
Old 12-11-2013
Ranges are charracter classes in regular expressions, not integer values, the range you created is 0..252 ie. the set (0,1,2,5,2) however ranges need to be used in a suitable tool rather than directly in the shell
One, horrendously complex, way of doing it would be to capture the digits and assess them separately like below, there is probably a much neater solution though...
$ myfile=vout123
$ export myfile
$ perl -e 'if ($ENV{myfile}=~/vout(\d+)/ && $1 >0 && $1 <253){print "t\n";}'

# 3  
Old 12-11-2013
There are several different kinds of confusion in there.

You cannot use == inside [ ] brackets, it needs [[ ]] brackets.

And == does not understand number ranges anyway. It understands characters.

Try a case statement:

case "$VAR" in
abcd[0-9])  echo stuff ;;
abcd[1-9][0-9])  echo stuff ;;
abcd1[0-9][0-9]) echo stuff ;;
abcd2[1-4][0-9]) echo stuff ;;
abcd25[0-2]) echo stuff ;;
*) echo "not matched" ;;

Or you could try stripping out the number first and just comparing that.
This User Gave Thanks to Corona688 For This Post:
# 4  
Old 12-11-2013

One more approach with awk.

echo $VAR | awk '/[a-z]{3}[0-9]{3}/ {print "Matched"}; /![a-z]{3}[0-9]{3}/ {print "NOT matched"}'

where var variable have the values.

R. Singh
# 5  
Old 12-12-2013
Originally Posted by Corona688
Or you could try stripping out the number first and just comparing that.
Perhaps like this:
$ echo $mynumber
$ if [ ${mynumber#????} -ge 0 ] && [ ${mynumber#????} -le 252 ]
> then
>    echo 't'
> else
>    echo 'f'
> fi

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