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Top Forums Shell Programming and Scripting Date variable in shell script Post 302463674 by cabrao on Monday 18th of October 2010 07:31:27 AM
Old 10-18-2010
Code:
$ DATE=20101018121445
$ DATE2=`echo $DATE | cut -c1-8`
$ echo $DATE2
20101018

This User Gave Thanks to cabrao For This Post:
 

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BASENAME(3)								 1							       BASENAME(3)

basename - Returns trailing name component of path

SYNOPSIS
string basename (string $path, [string $suffix]) DESCRIPTION
Given a string containing the path to a file or directory, this function will return the trailing name component. PARAMETERS
o $path - A path. On Windows, both slash ( /) and backslash ( ) are used as directory separator character. In other environments, it is the forward slash ( /). o $suffix - If the name component ends in $suffix this will also be cut off. RETURN VALUES
Returns the base name of the given $path. EXAMPLES
Example #1 basename(3) example <?php echo "1) ".basename("/etc/sudoers.d", ".d").PHP_EOL; echo "2) ".basename("/etc/sudoers.d").PHP_EOL; echo "3) ".basename("/etc/passwd").PHP_EOL; echo "4) ".basename("/etc/").PHP_EOL; echo "5) ".basename(".").PHP_EOL; echo "6) ".basename("/"); ?> The above example will output: 1) sudoers 2) sudoers.d 3) passwd 4) etc 5) . 6) NOTES
Note basename(3) operates naively on the input string, and is not aware of the actual filesystem, or path components such as " ..". Note basename(3) is locale aware, so for it to see the correct basename with multibyte character paths, the matching locale must be set using the setlocale(3) function. SEE ALSO
dirname(3), pathinfo(3). PHP Documentation Group BASENAME(3)
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