If I do "ls -l filename" in a script, it should return something like this:
-rw-r--r-- 1 user group 5945 Feb 28 14:24 filename
How do I put each of the above strings into a different variable?
eg Permissions, username, groupname, date (7 Replies)
Hi Guys,
I want to extract users environment variables via a sh script, and for some reason it is not working.
According to the su man page: Example 3: Executing command with user bin's Environment and
Permissions
To execute command with the temporary environment and per-... (2 Replies)
I've been trying to get the syntax right so I can echo a $var and then text around it or after it. It either wont display text or $var or one overwrites the other at the beginning of the line. Trying to do something like this.
var=1
echo $var"+1.1"
#output expected 1+1.1
Its an older... (3 Replies)
hi all,
I'm trying to automate some tasks and while I've got the script itself working, I'm having difficulties with automatic file detection and associated variable setting...
for example, in a directory I've got several files... something along the lines of:
xis0_NAME_src.file... (2 Replies)
Hello,
I need some help,
I got a CSV file called test.txt with this text in it :
08/02/2011;0,677;0,903;1,079;1,336;1,513;1,683
There's only a line and i need to copy theese numbers into variables :
0,677
0,903
1,079
1,336
1,513
1,683
The output file should look like this... (5 Replies)
Hello Everyone,
I am looking for a way to extract substrings to local variables. Here is the format of the string variable i am using :
/var/x/www && /usr/x/share/doc && /etc/x/logs
where the substrings i must extract are the "/var/x/www" and such.
I was originally thinking of using... (15 Replies)
Hi UNIX Members,
I've been tasked with performing the following:
Extract a block of data in column form
#This data changes each time, therefore automating future procedures
Please Note the following:
line = reading a line from a file_list that leads to the data
The filename is called... (16 Replies)
This is the file which contains only neccessary values from the output of curl command i.e TEMP_FILE
Proxy Hostname
server0123.domain.com
Proxy IP address
XXX.XXX.XX.XX port 0000
Proxy Version
SGOS X.X.X.X
Proxy Serial #
... (5 Replies)
Hello, new to the forums and to awk. Glad to be here. :o
I want to pass two shell (#!/bin/sh) variables through to awk and use them. They will determine where to start and stop text extraction.
The code with the variables hard-coded in awk works fine; the same code, but with the shell... (7 Replies)
Discussion started by: bedtime
7 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)