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Top Forums Shell Programming and Scripting 20090620231013 to date format i am using substr, any simple way in perl? Post 302327807 by jimmy_y on Monday 22nd of June 2009 03:48:00 PM
Old 06-22-2009
20090620231013 to date format i am using substr, any simple way in perl?

Hi Everyone,

$tmp[2]="20090620231013";
$tmp[2] = substr($tmp[2],0,8)." ".substr($tmp[2],8,2).":".substr($tmp[2],10,2).":".substr($tmp[2],12,2);

So my output is:
20090620 23:10:13.

I only can think substr is easy, any perl can do this just one line very simple efficient one? Smilie

Thanks
 

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tapset::string(3stap)													     tapset::string(3stap)

NAME
tapset::string - systemtap string tapset DESCRIPTION
strlen Returns the length of a string See function::strlen(3stap) for details. substr Returns a substring See function::substr(3stap) for details. stringat Returns the char at a given position in the string See function::stringat(3stap) for details. isinstr Returns whether a string is a substring of another string See function::isinstr(3stap) for details. text_str Escape any non-printable chars in a string See function::text_str(3stap) for details. text_strn Escape any non-printable chars in a string See function::text_strn(3stap) for details. - strtol Convert a string to a long See function::-strtol(3stap) for details. isdigit Checks for a digit See function::isdigit(3stap) for details. SEE ALSO
function::strlen(3stap), function::substr(3stap), function::stringat(3stap), function::isinstr(3stap), function::text_str(3stap), function::text_strn(3stap), function::-(3stap), function::strtol(3stap), function::isdigit(3stap), stap(1), stapprobes(3stap) IBM
--- tapset::string(3stap)
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