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Full Discussion: problem with sed
Top Forums Shell Programming and Scripting problem with sed Post 302279211 by JerryHone on Thursday 22nd of January 2009 05:52:30 AM
Old 01-22-2009
It's known as "greedy matching". The regular expression will always try and match the biggest string that satisfies the specified pattern, which in your case includes the embedded space.
In Perl, you can specify "non greedy" matching by following the * with a ?.

I think you could also have done...
Code:
echo ${kk}| sed -e 's/.*="\([0-9]*\) .* /\1/'

...to isolate the datestamp.

Jerry
 

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REGEX(3)						     Library Functions Manual							  REGEX(3)

NAME
re_comp, re_exec - regular expression handler SYNOPSIS
char *re_comp(s) char *s; re_exec(s) char *s; DESCRIPTION
Re_comp compiles a string into an internal form suitable for pattern matching. Re_exec checks the argument string against the last string passed to re_comp. Re_comp returns 0 if the string s was compiled successfully; otherwise a string containing an error message is returned. If re_comp is passed 0 or a null string, it returns without changing the currently compiled regular expression. Re_exec returns 1 if the string s matches the last compiled regular expression, 0 if the string s failed to match the last compiled regular expression, and -1 if the compiled regular expression was invalid (indicating an internal error). The strings passed to both re_comp and re_exec may have trailing or embedded newline characters; they are terminated by nulls. The regular expressions recognized are described in the manual entry for ed(1), given the above difference. SEE ALSO
ed(1), ex(1), egrep(1), fgrep(1), grep(1) DIAGNOSTICS
Re_exec returns -1 for an internal error. Re_comp returns one of the following strings if an error occurs: No previous regular expression, Regular expression too long, unmatched (, missing ], too many () pairs, unmatched ). 3rd Berkeley Distribution May 15, 1985 REGEX(3)
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