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Top Forums Shell Programming and Scripting Variable names within array call Post 302279071 by Annihilannic on Wednesday 21st of January 2009 11:48:40 PM
Old 01-22-2009
Assuming the variable containing the 0 is "var":

Code:
for i in `seq 0 23`; do
     let position=i*4+9
     tput cup 1 $position
     eval temp=\${cue_${var}[\$i]}
     case $temp in      # I want to replace the "0" in this line with a variable"
          0) printf "off" ;;
          1) printf "on" ;;
     esac
done

 

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RESET(3)								 1								  RESET(3)

reset - Set the internal pointer of an array to its first element

SYNOPSIS
mixed reset (array &$array) DESCRIPTION
reset(3) rewinds $array's internal pointer to the first element and returns the value of the first array element. PARAMETERS
o $array - The input array. RETURN VALUES
Returns the value of the first array element, or FALSE if the array is empty. EXAMPLES
Example #1 reset(3) example <?php $array = array('step one', 'step two', 'step three', 'step four'); // by default, the pointer is on the first element echo current($array) . "<br /> "; // "step one" // skip two steps next($array); next($array); echo current($array) . "<br /> "; // "step three" // reset pointer, start again on step one reset($array); echo current($array) . "<br /> "; // "step one" ?> SEE ALSO
current(3), each(3), end(3), next(3), prev(3). PHP Documentation Group RESET(3)
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