Hi Porter,

I debug the script and found out that:-

i) ++ echo '6/(' 5 '+6)'
++ bc
+ q=0

Does it means bc will round down the value? How can I get the exact value of division in this case?

ii) As I raised before, given the file has quite similar number.It will still print out all the possible number that found.

++ awk '{print $1}'
+ k='2:
3:'

This basically print the positions of file in c.txt(below) when 108 is grepped. Which means k=`grep -n "$char" c.txt|awk '{print $1}'` is not working to grab exact number.


2 0.959341 109
3 0.959341 108
4 0.797108 367
5 0.788534 83

iii)the (standard_in) 1: parse error comes in when the bc tries to calculate non value from (non match entry). Do you have any idea how to prevent the q to be calculate when the grep returns empty?
I tried to insert while and if inside but it returns me
./grep2.bash: line 49: syntax error near unexpected token `done'
./grep2.bash: line 49: `done '

Please help. Thanks.

-Jason