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Using cut

 
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# 1  
Old 10-18-2008
Using cut
I use
variable=`cut -f3 -d":" myfile`

myfile contains one record
field1:field2:/value1/value2/vlue3:field4,field5

variable returns value1value2value3 so I loode the /
I use cut because I had problems using awk -F

Either way any help is greatly appreciated.

Thanks
lcw
# 2  
Old 10-19-2008
what exactly you want?? i mean to say whats the expected output??
# 3  
Old 10-19-2008
Error
The only way I can think of for that to happen is if $IFS is set to "/" (which is done in some shell scripts to break a path into components; it should be changed back to the default immediately afterward). Perhaps show more of your script?
# 4  
Old 10-19-2008
Quote:
Originally Posted by vidyadhar85
what exactly you want?? i mean to say whats the expected output??
I want my $variable to contain value1/value2/vlue3 and not value1value2value3
Cut is stripping the '/'.

If there is another way to do this not using cut that will be also fine.

Thanks
# 5  
Old 10-19-2008
Quote:
Originally Posted by geekosaur
The only way I can think of for that to happen is if $IFS is set to "/" (which is done in some shell scripts to break a path into components; it should be changed back to the default immediately afterward).

Yes, that is correct.

btw, what is the error which you are getting while tried with awk?

Give a try on this.

Code:
x=`awk -F":" '{ print $3}' < file`

or
Code:
x=`sed 's/\(.*\):\(.*\):\(.*\):\(.*\)/\3/' < file`

# 6  
Old 10-19-2008
Quote:
Originally Posted by dennis.jacob
Yes, that is correct.

btw, what is the error which you are getting while tried with awk?

Give a try on this.

Code:
x=`awk -F":" '{ print $3}' < file`

or
Code:
x=`sed 's/\(.*\):\(.*\):\(.*\):\(.*\)/\3/' < file`

awk was perfect.

Thank you
# 7  
Old 10-19-2008
Code:
 
you can use:
 
 awk -F "/" '{print $2,$3,$4}'  file

 
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