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# 1  
Old 01-10-2008
simple awk question


I'm trying to use awk to print lines that match a regular expression.

I am using awk to print a record only if it contains N/A.

awk '/N/A/ {print $1}'

When executed the script returns "awk syntax error near line 1".

If I use /N//A/ it prints all records containing a "/", not just N/A

How can print the records with just the expresion N/A?

# 2  
Old 01-10-2008
escape the extra slash
awk '/N\/A/ {print $1}' file

# 3  
Old 01-11-2008 worked great Smilie

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In bash, grep -v -e '^[[:space:]]*$' filename.txt will filter all the blank lines from filename.txt and display the results.
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