awk + last occurrence


 
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# 1  
awk + last occurrence

Hi,
I'm attempting to search, using awk, a pattern range in a file. Something like:
>awk '/first bit of text.../,/...last bit of text/' file
Is it possible to print only the last (or first) occurrence of the pattern range this way?
Thanks for any suggestions.
Al
# 2  
from the top of my head - not easly and/or awk-natively, but:
Code:
/123/ {a=""}
# last
#/123/,/456/ {a=(a=="") ? $0 : a RS $0}

# first
/123/,/456/ {a=(a=="") ? $0 : a RS $0}
/456/ {exit}
END {
  print a
}

# 3  
Works great, thanks!
Al
 

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