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awk to find the number of occurrence

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# 1  
Old 01-16-2014
awk to find the number of occurrence
My file contains like this on 10 th line

NM1*IL*1*


Code:
awk '/NM1/{print NR}' *.dat

output is 10


Code:
awk '/NM1*IL*1*/{print NR}' *.dat

output is Nothing


but im expecting 10 on second code as well .
# 2  
Old 01-16-2014
Hello,

you should use like as follows. we should remove the special meaning for * by using \* in the code.


Code:
awk '/NM1\*IL\*1\*/ {print NR}' check_dtaa_dtaa1211
10


Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
Rajesh_us
# 3  
Old 01-16-2014
thanks a lot . it helps !
# 4  
Old 01-16-2014
Quote:
Originally Posted by Rajesh_us
My file contains like this on 10 th line

NM1*IL*1*


Code:
awk '/NM1/{print NR}' *.dat

output is 10


Code:
awk '/NM1*IL*1*/{print NR}' *.dat

output is Nothing

but im expecting 10 on second code as well .

print FNR instead of NR as your input is wildcard

Code:
$ awk '/pattern_to_search/{print FNR}' *.dat

This User Gave Thanks to Akshay Hegde For This Post:
Rajesh_us
# 5  
Old 01-16-2014
Thanks a lot
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