UNIX for Dummies Questions & Answers

Hi

I need to do an add function but it should include the prefixed zeros

For Example
i=00123
j=`expr $i + 1`

The output it shows is 124 but I want the output to be 00124

Could any one help me finding out how to do this

Thanks

hi,

i moved your post from "news, links, events announcements" to "UNIX for Dummies Questions & Answers" and closed the poll.

and, here is your answer:

Code:

root@mp-wst01 # i=00123
root@mp-wst01 # j=`printf %05d $(expr $i + 1)`
root@mp-wst01 # echo $j
00124

regards pressy

Hi

Thanks

I posted in the wrong group by mistake , Sorry about that

Regarding my query

I don't know what would be the length of the input string , actually 00123 would be the input from the user .The script would look like

read i
j=`printf %05d $(expr $i + 1)`
echo $j

The user can input 00123 or 0123 or 00000123 for which I want the output to be 00124 , 0124 , 00000124 respectively

Siva

Hi

I have put some simple logic in place to do the trick for me , the code now looks like

read variable
length=${#variable}
y=`expr $variable + 1`
length1=${#y}
if [ $length1 != $length ]
then
t=`expr $length - $length1`
i=1
ttt=$y
while [ $i -le $t ]
do
i=`expr $i + 1`
ttt=`echo "0$ttt"`
done
echo $ttt
else
echo $y
fi

Sample outputs are
$ ./ttt
9
10
$ ./ttt
99
100
$ ./ttt
1
2
$ ./ttt
100
101
$ ./ttt
01
02
$ ./ttt
00101
00102
$ ./ttt
009
010
$

However I still feel there could be some simple logic to do the same , any suggestions please ??

Thanks
SIva

What about this:

Code:

read variable
zeros=`echo $variable | sed 's/\(0*\)[1-9]*/\1/'`
y=`expr $variable + 1`
print $zeros$y

Regards,
Tayyab

That doesn't work. Here $ represents the ksh prompt...

Code:

$ set -x
$ read variable
+ read variable
001007
$ zeros=`echo $variable | sed 's/\(0*\)[1-9]*/\1/'`
+ echo 001007
+ sed s/\(0*\)[1-9]*/\1/
+ zeros=00007
$ y=`expr $variable + 1`
+ expr 001007 + 1
+ y=1008
$ print $zeros$y
+ print 000071008
000071008

Try this instead...

Code:

echo $variable | awk '{printf "%0*d\n",length,$1+1}'

Or...

Code:

printf "%0${#variable}d\n" $(expr $variable + 1)

Ygor you are right, script fails if there is any zero in number, what you suggest to fix this. Idea was to grab zero's until the first occurrence of any non-zero digit but it didn't work