UNIX for Dummies Questions & Answers

Hi guys,

I am thanks in advance for any posts and for reading. I am trying to run this script, under solaris:

echo "****************************************"
echo "The host is: "
echo "****************************************"
<<EOF find /etc/default -name login -exec ls -l {} \;
find /etc -name services -exec ls -l {} \;
find /etc -name shadow -exec ls -l {} \;
find /etc/dfs/ -name dfstab -exec ls -l {} \;
find /etc -name inetd.conf -exec ls -l {} \;
find /etc -name hosts.equiv -exec ls -l {} \;
find / -name .rhosts -exec ls -l {} \;
EOF
echo "***************************************"
echo " END OF RECORDS"
echo "***************************************"
exit 0

but its only printing off the first find line, anyone any ideas why the box isn't executing the rest of the script?

thanks again,

Marky Mark...

I resolved it but rescripting to this:


#!/bin/bash

#################################
#
# Script by Mark Newton
#
#################################

<<EOF_11 cd /
EOF_11
echo "****************************************"
echo " WORKING IN THE:"
<<EOF_12 pwd
EOF_12
echo "****************************************"
echo "****************************************"
echo "The host is: EURCOMUNX001"
echo "****************************************"

echo "******************"
echo "a) /etc/default/login"
echo "******************"

<<EOF find /etc/default -name login -exec ls -l {} \;
EOF

echo "******************"
echo "b) /etc/sevices"
echo "******************"

<<EOF_1 find /etc/ -name services -exec ls -l {} \;
EOF_1

echo "******************"
echo "C) /etc/shadow"
echo "******************"

<<EOF_2 find /etc -name shadow -exec ls -l {} \;
EOF_2

echo "******************"
echo "d) /etc/dfs/dfstab"
echo "******************"

<<EOF_3 find /etc/dfs/ -name dfstab -exec ls -l {} \;
EOF_3

echo "******************"
echo "f) /etc/hosts.equiv"
echo "******************"

<<EOF_5 find /etc -name hosts.equiv -exec ls -l {} \;
EOF_5

echo "******************"
echo "e) /etc/inetd.conf"
echo "******************"

<<EOF_14 find /etc/inet -name inetd.conf -exec ls -l {} \;
EOF_14


echo "*****************"
echo "g) ./rhosts"
echo "*****************"

<<EOF_6 ls -l .rhosts
EOF_6

echo "***************************************"
echo " END OF RECORDS"
echo "***************************************"
exit 0

Helo,
What do you want this script exactly to do?

Just literally long list a load of files so that I can get the file permissions, instead of doing an ls -l on the entire directory. Its for some audit thing... Anyhow we don't want to show every file under the directory hence the script...

If you just want the file list then (all one line):

Code:

ls -la /etc/default/login /etc/services /etc/shadow /etc/dfs/dfstab /etc/hosts.equiv /etc/inetd.conf /.rhost

If you want it all pretty-printed then how about simplifying it (and adding a "not found" message for completeness):

Code:

function printblock
{
echo "****************************************"
echo "$*"
echo "****************************************"
}

cd /
printblock "WORKING IN THE: $PWD"
printblock "The host is: EURCOMUNX001"

ptr=0
set -A tab a b c d e f g

for a in /etc/default/login /etc/services /etc/shadow /etc/dfs/dfstab /etc/hosts.equiv /etc/inetd.conf /.rhosts
do
  name=${tab[$ptr]}
  printblock "$name) $a"
  if [ -f $a ]; then
    ls -la $a
  else
    echo "File $a not found"
  fi
  ptr=$(($ptr + 1))
done

printblock "END OF RECORDS"
exit 0

I see your point, I might look into this. For min I think I will leave it as is...