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if statements in shell to compare value

 
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# 1  
Old 11-15-2011
[Solved] if statements in shell to compare value
Hi,

I am a newbie to unix, I am trying to write a shell script (just a test) but I can't seem to compare the variable value with a string in the if statement.

I get an error when i execute the following script, could you tell me what is wrong and how I can correct it

Note - I am using bash

pasted below is the shell script:


Code:
parameter1=""

if($1 == "-l") then
    $parameter1="-l"
else
    $parameter1="-ltr"
fi

command="ls ${parameter1}"

echo $command

Thanks,
muthu
Last edited by muthuveerappan; 11-15-2011 at 10:07 AM..
# 2  
Old 11-15-2011
Code:
parameter1=""

if ( "$1" == "-l" ) ; then
    parameter1="-l"
else
    parameter1="-ltr"
fi

command="ls ${parameter1}"

echo $command

Last edited by vbe; 11-15-2011 at 10:23 AM..
# 3  
Old 11-15-2011
Since I don't know bash...
Code:
#!/usr/bin/ksh
parameter1=""

if [ "$1" == "-l" ]
then
    parameter1="-l"
else
    parameter1="-ltr"
fi

command="ls $parameter1"

echo $command
#-----
# execution:
n12:/home/vbe $ ./002
ls -ltr
n12:/home/vbe $ ./002 -l 
ls -l

This User Gave Thanks to vbe For This Post:
muthuveerappan
# 4  
Old 11-15-2011
So possible errors: spaces required... ; then etc...
# 5  
Old 11-15-2011
Thanks a lot !!
Thanks a lot !! works great !! Smilie
 
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