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how to compare text value in shell

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# 1  
Old 06-19-2007
how to compare text value in shell
Hi,

I need to check that if user is not oracle the the script should exit out .
But the below script always exits evenif I am logged as oracle.

Plz help me...........

USER=`id`
echo $USER

if [ "$USER" != "oracle" ]; then
echo " You are logged as `id` , it must be oracle "
exit 2
fi

Regards
# 2  
Old 06-19-2007
Quote:
Originally Posted by reply2soumya
USER=`id`
Instead of `id` use `whoami`
# 3  
Old 06-19-2007
Quote:
USER=`id`
echo $USER

if [ "$USER" != "oracle" ]; then
echo " You are logged as `id` , it must be oracle "
exit 2
fi

Code:
#!/bin/bash
USER=`whoami`
echo $USER

if [ "$USER" != "oracle" ]; then
echo " You are logged as $USER , it must be oracle"
exit 2
fi

Output:

Quote:
Compaq
You are logged as Compaq , it must be oracle
The best way to check your script is to debug it. if you would have used the sh -x option, you would have seen for itself that id command returns not the username but a lot of information.

Quote:
$ sh -x soumya
++ id
+ USER='uid=1006(Compaq) gid=513(None) groups=0(root),513(None),544(Administrato
rs),545(Users),1007(Debugger Users)'
+ echo 'uid=1006(Compaq)' 'gid=513(None)' 'groups=0(root),513(None),544(Administ
rators),545(Users),1007(Debugger' 'Users)'
uid=1006(Compaq) gid=513(None) groups=0(root),513(None),544(Administrators),545(
Users),1007(Debugger Users)
+ '[' 'uid=1006(Compaq) gid=513(None) groups=0(root),513(None),544(Administrator
s),545(Users),1007(Debugger Users)' '!=' oracle ']'
++ id
+ echo ' You are logged as uid=1006(Compaq) gid=513(None) groups=0(root),513(Non
e),544(Administrators),545(Users),1007(Debugger Users) , it must be oracle '
You are logged as uid=1006(Compaq) gid=513(None) groups=0(root),513(None),544(A
dministrators),545(Users),1007(Debugger Users) , it must be oracle
+ exit 2
Hope this helps !!!!
kamitsin
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