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Remove part of file name with sed & mv

 
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# 1  
Old 06-19-2011
Remove part of file name with sed & mv
Ok, so I have bunch of files that are named "orange__file_name.asm" and I want to batch rename them to "file_name.asm" I know that using "ls | sed s/orange__//" will get rid of the part of the file name I do not want. But how do I combine that with the mv command to actually do it?

Thanks

JG
# 2  
Old 06-19-2011
If you are using Kshell or bash, I'd suggest something like this:

Code:
ls | while read f
do
   mv $f ${f#*__}
done

The ${f#*__} removes everything from the start of the filename through the first __.

If you want to test before running it, add echo before the move and it will just echo the move commands back to the tty instead of executing them (be sure before being destructive).
This User Gave Thanks to agama For This Post:
frankos
# 3  
Old 06-20-2011
That does not seem to work for some reason. I'm using Bash on OsX.
I get this message: "usage: mv [-f | -i | -n] [-v] source target"
# 4  
Old 06-20-2011
Try echo mv, to see what you're actually getting.
# 5  
Old 06-20-2011
OK. I take it back, it works. I had some files with a space in the file name and it did not work on those. It did work on everything else though. How can I make it work of files with spaces in the name as well? Anyway, agama & Corona688 you helped a lot. Thank you. Agama for posting a solution and Corona688 to make me look at the output again :-)
# 6  
Old 06-21-2011
Quote the filename on the mv command. Always a good practice, though I don't make a habit of it because we insist that filenames do not contain spaces.

Code:
mv "$f" "${f#*__}"

And, you are most welcome.
 
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