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sed converting / to \/

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# 1  
Old 12-12-2006
sed converting / to \/
Hi all,
I am using sed for converting a string of type /abc/def/gh by \/abc\/def\/gh

[trainee@LINUX ~]$ edu="/home/abc/dec"

When I echo that variable and pass it to sed ,it works fine...
[trainee@LINUX ~]$ echo $edu|sed 's/\//\\\//g'
\/home\/abc\/dec

But When I try to store in a variable , it shows the following error Smilie
[trainee@LINUX ~]$ ued=`echo $edu|sed 's/\//\\\//g'`
sed: -e expression #1, char 9: unknown option to `s'

HELP BLEAZ
Last edited by sakthi.abdullah; 12-12-2006 at 09:23 AM..
# 2  
Old 12-12-2006
Code:
echo "a/b/d" | sed 's#/#\\/#g'

When you are using sed to work with "/" characters you have to use another delimiter - in this case I picked "#"
# 3  
Old 12-13-2006
Can you explain this further because
Usually it's of the form s/old/new/g but sed 's#/#\\/#g' contains only s/.../g
# 4  
Old 12-13-2006
Quote:
Originally Posted by jim mcnamara
Code:
echo "a/b/d" | sed 's#/#\\/#g'

When you are using sed to work with "/" characters you have to use another delimiter - in this case I picked "#"
Again, echo "a/b/d" | sed 's#/#\\/#g' ll work fine.... But What I need is something like this ..how can I store that value on to a variable
like abc=`echo "a/b/d" | sed 's#/#\\/#g'`
# 5  
Old 12-13-2006
Quote:
Originally Posted by sakthi.abdullah
abc=`echo "a/b/d" | sed 's#/#\\/#g'`
Turn the backticks into $(...). See this.

Code:
[~]$ abc=`echo "a/b/d" | sed 's#/#\\/#g'`
[~]$ echo $abc
a/b/d
[~]$ abc=$(echo "a/b/d" | sed 's#/#\\/#g')
[~]$ echo $abc
a\/b\/d
[~]$

Hmm.. I am a little surprised with the difference in behaviour of `...` and $(...) Smilie

Edit
Ah ! Here's how it goes with the backticks.
Code:
[/tmp]$ abc=`echo "a/b/d" | sed 's#/#\\\\/#g'`
[/tmp]$ echo $abc
a\/b\/d

And here's why. From man sh
Code:
       When  the  old-style  backquote  form of substitution is used, backslash
       retains its literal meaning except when followed by $,  ?,  or  \.   The
       first  backquote not preceded by a backslash terminates the command sub-
       stitution.  When using the $(command) form, all characters  between  the
       parentheses make up the command; none are treated specially.

/Edit
Last edited by vino; 12-13-2006 at 01:22 AM..
# 6  
Old 12-13-2006
Backtick version:
abc=`echo "a/b/d" | sed 's#/#\\\\/#g'`

but I strongly prefer $(...) to `...` for many reasons.
# 7  
Old 12-14-2006
Quote:
Originally Posted by Perderabo
Backtick version:
abc=`echo "a/b/d" | sed 's#/#\\\\/#g'`

but I strongly prefer $(...) to `...` for many reasons.
Can you please mention those ..
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