UNIX for Advanced & Expert Users

sorry.. i quickly created a directory structure in my machine.. so i put the folder name as wrong..

Also, when you pass the directory name as argument to your script, make sure you pass the absolute path

change it to

Code:

 
../b/$i ---> a2/$i

Hi,

I think this is what you are looking for,

Code:

#! /usr/bin/bash
 
dir1=$1;
dir2=$2;
base=$3;
 
if [ $# != 3 ]
then
echo "Script Usage: $0 dir1 dir2 basedir";
exit;
fi
for file1 in `ls $dir1`
do
   for file2 in `ls $dir2`
   do
      if [ "$file1" = "$file2" ]
      then
        `\rm -rf "$base/$file1"`;
         echo "$base/$file1";
      fi
      if [ -s "$dir1/$file1" -a -s "$dir2/$file2" ]
      then
         a=`diff "$dir1/$file1" "$dir2/$file2" | wc -l`;
         if [ $a = 0 ]
         then
            `\rm -rf "$base/$file1"`;
         fi
      fi
   done
done

Cheers,
Ranga

@rangarsan
Sorry, but your script is really dangerous and contains serious design errors and basic syntax mistakes.
Strongly advise that the O/P ignore this post.

I have written this code in sun solaries with bash and executed it. Its working fine in that. what is the syntax error do you found and you mean dangerous code. may i know what it would be? This is the requirement which every one found in the first post. please revert if you have any quries.

Cheers,
Ranga

@rangarasan

Danger:
The main issue is that the script will issue "rm -rf" on any unique directory which your "ls" finds. You should not have the "-r" parameter in this script.
Even if it is a file, the script deletes the files from the wrong directory.
Part of this is pandeesh's really vague specification of the third parameter. I actually believe that he meant to "move" not "remove" the files to the third directory.

Design:
Any names containing space characters will get split into partial names.
itkamaraj's code does not have this problem, but it does have other problems.
The script repeatedly searches $dir2 for matching names one-by-one (inefficient and avoidable).
There is no check that what is output by "ls" is actually a file. It could be a directory in which case we have a disaster.

Syntax:
This is unix not Oracle. There is never a reason to end a line in Bourne-type script with a semi-colon. You have many lines like that.
Never use backticks in a standalone line. It will not always behave.
Presumably the "\rm" is to avoid an alias for "rm" on your system.
That single line contains more errors than I have seen in a single line for some time.



Forgot to mention that pandeesh should probably have been looking at the unix "dircmp" command.