Shell Programming and Scripting

hi All,

I have the following two requirements:
case 1:
In a file i have the below code:

Code:

 
if ((a>b)) a=b;
else a = c;

by using some means i need to convert the line to the following output:
Output required:
case 2:
In a file i have the below code:

Code:

 
if (a>b) 
 a=b;
else 
 a = c;

Output required:

Hi,

try sed with:

Code:

sed "s/a\s*=\s*b;/\n{\n&\n}/;s/a\s*=\s*c;/\n{\n&\n}/" file

\n means newline, \s* means followed by none or more spaces, & stand for the matched string. The second case is basically the same.

HTH Chris

Chris, I need to put the { by checking the presence of ")" .The content a,b can be anything..

Also the output is
not the required.

Yeah, you didn't tell which flavour of unix you are unix.
Now we know, you sed doesn't know \n as newline.

To make the regexp more general, save this in a file "regexp":

Code:

s/^\(\s*if\s*(\+.*)\+\)\s*\(.*\)/\1\
{\
\2\
}/;s/\(^\s*else \)\(.*\)/\1\
{\
\2\
}/

\n is now represented as \ at the lineend. It matches case 1. To convert case2 to case1, try:

Code:

sed -n '$! N;s/\
//p' file >> file2

Now you can use sed with:

Code:

sed -f regexp file

If have tested it for both of you case on my Linux box.

But most probably what you are looking for is a indenter like "indent".
Trying to match all possible cases over multiple lines with regexp get slow pretty fast.

HTH Chris