Desperate for help with menu coding


 
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Top Forums Shell Programming and Scripting Desperate for help with menu coding
# 8  
Old 12-11-2007
Quote:
Originally Posted by sinjin
I'm not using Solaris 9. I'm just using plain, ol' Unix from what I know. I'm still getting the error message that option is an undefined variable.

(a) type "uname -a" and post results

(b) post your script within CODE brackets as I have done

(c) your UNIX does not support "/bin/sh" ?
# 9  
Old 12-11-2007
AIX lc3bd1 3 4 00016D4F4C00
# 10  
Old 12-11-2007
... and post your code in [ CODE ] brackets as I have done...
# 11  
Old 12-11-2007
Code:
#!/bin/csh

cat <<ENDINPUT

Menu of Options

1. Display all files in a user's home directory
2. Welcome yourself to the program
3. Display System Information
4. Exit back to Windows

ENDINPUT
echo Please enter your choice:
read option
case "$option" in

1)
   ls -l
   ;;
2)
   echo welcome
   ;;
3)
   uname -a
   ;;
4)
   exit
   ;;
*)
   echo "Use 1, 2, 3, or 4"
   ;;
esac

# 12  
Old 12-11-2007
So when I suggest you change the line

Code:
#!/bin/csh

to
Code:
#!/bin/sh

what did you think I meant?
# 13  
Old 12-11-2007
Porter,

Well, I made the switch to /bin/sh as you recommended. Sorry, I didn't see that earlier or wasn't paying attention. I am now able to execute options 2 and 3. However, when I enter 1 or 4, it says the following:

ksh: 1: not found
or for option 4
ksh: 4: not found

Plus, I wasn't thinking but after entering one of these options except #4, I need to be able to bring the menu back up.
# 14  
Old 12-11-2007
Quote:
Originally Posted by sinjin
ksh: 1: not found
or for option 4
ksh: 4: not found
That's because you fell out of the menu script and are expecting the ksh shell to understand your menu options.

Did you notice my "while true; do ...... done"?
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