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While loop help

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# 1  
Old 03-28-2014
While loop help
Hi

I am trying to create a script that would check % column of a particular file system and if that number is greater than 91, it should send an email to the admin. What I wrote so far is this:
Code:
#!/bin/sh
#check if /backups is greater than 91%

VALUE=df -h /backups | awk '{ print $5 }'

while [ $VALUE gt 91 ]; do
echo "check /backup F.S." | mailx -s "/backups on moneta" admin@company.com
done

But the problem I am facing is the variable
Code:
VALUE

is not set properly.
Please can you help
# 2  
Old 03-28-2014
Code:
#!/bin/sh
#check if /backups is greater than 91%

VALUE=$(df -h /backups | awk '{ print $5 }')

while [ $VALUE -gt 91 ] 
do
   echo "check /backup F.S." | mailx -s "/backups on moneta" admin@company.com
done

# 3  
Old 03-28-2014
Code:
#!/bin/sh
#check if /backups is greater than 91%

VALUE=$(df -h /backups | awk '{ print int($5) }')

if [ "$VALUE" -gt 91 ]; then
   echo "check /backup F.S." | mailx -s "/backups on moneta" admin@company.com
fi

# 4  
Old 03-28-2014
while loop help
I am getting the following error:
Code:
 # ./check_backups.sh
./check_backups.sh: syntax error at line 4: `VALUE=$' unexpected

# 5  
Old 03-28-2014
Quote:
Originally Posted by vbe
Code:
#!/bin/sh
#check if /backups is greater than 91%

VALUE=$(df -h /backups | awk '{ print $5 }')

while [ $VALUE -gt 91 ] 
do
   echo "check /backup F.S." | mailx -s "/backups on moneta" admin@company.com
done

If you had bothered to tell us you were using a Solaris system, vbe and Franklin52 would have known that your shell wouldn't recognize $(command) substitution.

Try:
Code:
#!/bin/sh
#check if /backups is greater than 91%

VALUE=`df /backups | awk '{ print $5 }'`

if [ "$VALUE" -gt 91 ] 
then
   echo "check /backup F.S." | mailx -s "/backups on moneta" admin@company.com
fi[

Note that I left off the -h because there really isn't any need to make df spend extra cycles to produce human readable output that is only going to be read and thrown away by awk.
This User Gave Thanks to Don Cragun For This Post:
fretagi
# 6  
Old 03-28-2014
on advice from Franklin52, my script:
Code:
#!/bin/sh
#check if /backups is greater than 91%

VALUE=$(df -h /backups | awk '{ print int($5) }')

if [ "$VALUE" -gt 91 ]; then
echo "check /backup F.S." | mailx -s "/backups on moneta" fretagi@mcel.co.mz
fi

and the output was:

Code:
 ./check_backups.sh
./check_backups.sh: syntax error at line 4: `VALUE=$' unexpected

---------- Post updated at 11:47 AM ---------- Previous update was at 11:46 AM ----------

my apologies it is solaris 10, I will change now

---------- Post updated at 11:52 AM ---------- Previous update was at 11:47 AM ----------

It is now working fine. I guess I now need to insert on
Code:
crontab

to run every hour.

---------- Post updated at 12:05 PM ---------- Previous update was at 11:52 AM ----------

for some reason, something is not quite right because:
Code:
df -h /backups/
Filesystem             size   used  avail capacity  Mounted on
/dev/md/dsk/d600       1.5T   1.1T   458G    71%    /backups
You have new mail in /var/mail//root

BUT the script is sending me an email saying that it has passed the 91% mark

---------- Post updated at 12:08 PM ---------- Previous update was at 12:05 PM ----------

I know why, its because I left out
Code:
-h

# 7  
Old 03-28-2014
Replace this line:

Code:
VALUE=`df -h /backups | awk '{ print int($5) }'`

with:
Code:
VALUE=`df -h /backups | awk 'NR-1{ print int($5) }'`
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