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Script to sort by size of directories

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# 1  
Old 11-19-2013
Script to sort by size of directories
Hello,

I'm trying to find top 5(highest) directories by size. I did something like
Code:
du -sh * > $file

Where I can get all the size with respect to directories, but I need only top 5 directory from the file. How can I sort by size in the file and print top 5 sizes with the directory name???

Please suggest me to move further.

Output of the "file" is like below

Code:
4.0K    a
4.3M    dl
131G    he
8.0K    an
8.5G    ss
208K    be
4.0K    ng
5.1G    un
4.0K    e
65G     vm
6.9G    dch
4.0K   au
196K    iq
4.0K    jc
4.0K    es
27G     wr
4.0K   rs
5.7M    jk
52G     da
4.0K    jvk
4.8M    god
4.5G    is
12K    vs

# 2  
Old 11-19-2013
Try:
Code:
du -sk * | sort -nrk1 | head -5

This User Gave Thanks to bartus11 For This Post:
pjeedu2247
# 3  
Old 11-20-2013
Hi.

See https://www.unix.com/shell-programming-and-scripting/182403-how-sort-numbers-symbol-like-alphabets-5m-52g.html for an alternate suggestion, namely a new option for "human-readable" data with recent versions of GNU sort.

Best wishes ... cheers, drl
This User Gave Thanks to drl For This Post:
pjeedu2247
# 4  
Old 11-20-2013
Thanks alot guys, that helped a lot.

I appreciate your help.

---------- Post updated at 06:02 PM ---------- Previous update was at 10:26 AM ----------

I got this trouble with some other basic issue. But my poor scripting skills don't know how to fix this.

Code:
du -sk * | sort -nrk1 | head -5 > /kjor/space

awk '{ printf("%.3f GB\n", $1 / (1024*1024)); }' $1 cat /kjor/space

Output as

Code:
13.554 GB 
8.556 GB
20.889 GB
4.013 GB 
3.296 GB

Instead of

Code:
13.554 GB    an
8.556 GB    ss
20.889 GB    be
4.013 GB    ng
3.296 GB    gt

Can you suggest me how to print output without changing the actually alphabets ??
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