Having a little trouble with grep

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# 8  
Old 11-03-2013
You must allow some characters in between
ls -l | grep '^[l].*'"$argv[1]"'$'

Or shorter
ls -l | grep '^l.*'"$1"'$'

This User Gave Thanks to MadeInGermany For This Post:
# 9  
Old 11-03-2013
You need to allow some characters in between.
 ls -l | grep '^l.*softlink.txt'

The "." matches any single character and "*" means that the preceding item, any character, will be matched zero or more times.
# 10  
Old 11-03-2013
The argument you passed to grep will only match the line:
l "$argv1"

There is a big difference between single quotes and double quotes, and double quotes inside single quotes are taken as literal characters.
# 11  
Old 11-03-2013
I got it to work by using MadeInGermany's suggestion. Would you be able to explain what happened so I can understand? What do the second pair of single quotes around "$argv[1]" actually help it do to work? When you say the single quotes around that help make it a literal character, that the single quotes actually make what's inside the parenthesis an actual string, while argv[1] gets put into softlink.txt?
# 12  
Old 11-03-2013
Not around the "$argv[1]".
For the shell it is a concatenation of three strings

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