Shell Programming and Scripting

Does anyone know how I can add a variable to a one line perl command such as the following:

#! /bin/bash
date=`date +%Y%m%d`
perl -i -pe 's/(1\.1\.0\.).+/${1}${date}/' ./build_date

I'd like the ${date} variable to be evaluated by the perl command. So that the perl command will read each line of the file ./build_date and replace each line that contains '1.1.0.yyyymmdd' with 1.1.0.${date}.

Try this:

Code:

#!/bin/bash

export date=`date +%Y%m%d`
perl -i -pe 's/(1\.1\.0\.).+/${1}$ENV{"date"}/' ./build_date

That works, thanks.

I was trying to figure out how to do it with $ARGV[0] by passing an argument to the perl command.