Hi
Is there any way to use UNIX and Perl to automate sending e-mail. I got a dynamic changing file that send out to people in my mailing list and want to experinment to see if Perl and UNIX can send it out for me when the content is change. I found a Perl source code but dont really know how to... (4 Replies)
hi..
I am new to perl and have just downloaded the whole perl man directory in html (so I am a little serious about learining how to use it.. ) the only problem is I am hardly getting anything edge wise so far.. except for some basic file scripting.. what I would like to know is how would you use... (2 Replies)
Hi,
My perl script takes few switches which i'm parsing through GetOpt::Long module.
My script looks like something :
myscript.pl --file="foo" --or --file="bar"
The --file switch takes 2 arguments foo and bar.
The 2 values of file are separated by --or switch. I want to ensure that... (1 Reply)
I had posted previously about this problem I had.
I have multiple text files with hundreds of lines of the following type:
2000001 34 54 234 2000001
32 545 2000001 -2000001 77 2000001 44 2000001 998 2000001
77 32 2000001 45 23 111 89
98 75 23 34 999
.
.
.
etc...
What I wanted was... (2 Replies)
Hi all,
I want to get options from command line by perl.
usage()
options:
-h Show this help message and exit
-t Name of tester
--timeout Set the timeout
-l ... (1 Reply)
Hi,
I use find command to list all the files in a directory and its sub-directories, but the problem is to exclude certain directories during search. Can i give the directory names in command line to skip them and search rest of the directories?
For example i have directories:
test
../test1... (1 Reply)
so in unix this command works works and shows me a list of directories
find . -name \*.xls -exec dirname {} \; | sort -u | > list.txt
but when i try running a perl script to run this command
my $query = 'find . -name \*.xls -exec dirname {} \; | sort -u | > list.txt';... (2 Replies)
how do i check if a command line argument is -g?
for example,
if command line argument equals "-g"
{
print "Goodbye \n";
}
else
{
print "Welcome to the program! \n";
} (1 Reply)
Hi
I need to write a Perl script that the file given as first argument of the command line that will find all occurrences of the string given as the third argument of the command line and replace with the string given as the fourth argument. Name newfound file is specified as the second... (3 Replies)
I am looking for help in processing of those options: '-n' or '-p'
I understand what they do and how to use them.
But, I would like to use them with more than one file (and without any shell-loop; loading the 'perl' once.)
I did try it and -n works on 2 files.
Question is:
- is it possible to... (6 Replies)
Discussion started by: alex_5161
6 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)