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Passing variable as an argument to another script


 
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# 8  
Old 09-13-2013
The problem is in how the shell is interpreting the $a at the invocation of the other script. $a is interpreted as 3 arguments because three are two whitespace in $a. "$a" is interpreted as a single argument because it sees the quotes around the $a. Use my solution: eval causes the shell to interpret the $a as two arguments, which is what you need.

Andrew
# 9  
Old 09-13-2013
You will have to split it
Code:
a="-b"; b="\"FPT MAIN\" ";set -x ; ./test.sh $a "$b"; set +x

--ahamed

---------- Post updated at 01:27 AM ---------- Previous update was at 01:25 AM ----------

Or you can do it like Adrew said

--ahamed
# 10  
Old 09-13-2013
Thanks Andrew.

It worked with eval.

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