Bin iteratively based on each row

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# 1  
Old 08-25-2013
Bin iteratively based on each row

I have a file some thing like below. I want to bin the data. My Bin size is 100.
items	number
HELIX1	75 
HELIX6	160    
HELIX2	88    
HELIX19	114   
HELIX5	61    
HELIX4	167

it should consider each elemet under the number column and bin all the lines like below with 100 as an interval. The third column should represent the bin range
HELIX1	75	75-175	   
HELIX2	88	75-175    
HELIX19	114	75-175
HELIX6  160	75-175 
HELIX4	167	75-175

HELIX6  	160	160-260	
HELIX4       167	160-260

HELIX2	88	88-188		   
HELIX19	114	88-188
HELIX6  160	88-188	
HELIX4	167	88-188

and so on based on the number of rows in inpit file

when i searched in the forum i found some thing like this
awk '{f=sprintf("%d", 1+$2/100); fn[f]="bin"f"_"; print $1,$2>>fn[f]}' file_name

which bins from 0-100 and so on
# 2  
Old 08-25-2013
Not sure where you want to start your bins? At 0? at 75? at 88?
# 3  
Old 08-25-2013
The first element in the number column is 75 so it should bin from 75-175; second element is 160, so bin elements that occur between 160-260 ; and third element is 88 so it has to bin 88-188; fourth element is 114 so 114-214 and so on for each element in the number column.
# 4  
Old 08-25-2013
Perhaps something like this:
awk '
    for(i in B) {
      r=i "-" B[i]
      if ( i+0<=$2+0 && $2+0 < B[i]+0 ) print $0, r > ( "bin_" r )
' OFS='\t' file file

Last edited by Scrutinizer; 08-25-2013 at 03:24 PM..
# 5  
Old 08-25-2013
For my trial data set the code provided is not producing any result i am using cygwin
# 6  
Old 08-25-2013
I corrected it in my post. The input file needs to be specified twice..
This User Gave Thanks to Scrutinizer For This Post:
# 7  
Old 08-25-2013
Thank you it works perfectly could you please explain how it works
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