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Scripting Question - getting lines above ane below certain enteries


 
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# 1  
Old 08-20-2013
Scripting Question - getting lines above ane below certain enteries

Hello -
I have a file in the followig format

Code:
LINE TEXT 1
Line TEXT 2
TIMESTARTED=Fri Aug 16 15:20:23 EDT 2013
START-OF-DATA
123
123444
23232323
END-OF-DATA
Line TEXT 9

I need to get all the lines between the Start of Data and End of Data and pipe it to a file so output should be

Code:
123
12344
2332323


Can you please recommed a command line option that could work
maybe using Awk Sed Grep ?

Thanks

Last edited by Scrutinizer; 08-20-2013 at 04:12 PM.. Reason: code tags
# 2  
Old 08-20-2013
Code:
sed -n '/^START-OF-DATA/,/^END-OF-DATA/{//!p};' file | tee outfile
123
123444
23232323

cat outfile
123
123444
23232323

# 3  
Old 08-20-2013
Code:
sed -n '
    /^START-OF-DATA/,/^END-OF-DATA/{
        /-OF-DATA/d
        w outfile
    }
 ' file

# 4  
Old 08-20-2013
awk
Code:
awk '/START-OF-DATA/{f=1;next} /END-OF-DATA/{f=0} f' file

# 5  
Old 08-20-2013
thank you both -- I will try both and let you know how it goes
Really appreciate it!!
# 6  
Old 08-20-2013
Placing the conditional print (p or p!=0 {print}) after the conditional {p=0} and before the conditional {p=1} saves a next
Code:
awk '/END-OF-DATA/{p=0} p; /START-OF-DATA/{p=1}' file

In general it's more robust to process the end condition only after the start condition was met
Code:
awk 'p&&/END-OF-DATA/{p=0} p; /START-OF-DATA/{p=1}' file


Last edited by MadeInGermany; 08-20-2013 at 10:18 PM..
This User Gave Thanks to MadeInGermany For This Post:

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