Extract First and matching word from string in UNIX

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# 1  
Old 08-19-2013
Thank you

Last edited by Pratik Majithia; 09-19-2013 at 05:56 AM..
# 2  
Old 08-19-2013
 awk '{a=$1;} gsub(/\(/, " (") gsub(/\)/, " )") {for(i=2;i<=NF;i++) {if(substr($i,1,5)=="$dwh.") a=a" "substr($i,6)}} {print a}' file.sql

# 3  
Old 08-19-2013
Fixed some on krishmaths code (removed extra bracket and gsub)
awk '{a=$1;gsub(/[()]/," ");for(i=2;i<=NF;i++) {if(substr($i,1,5)=="$dwh.") a=a" "substr($i,6)};print a}' file.sql

awk '{
	gsub(/[()]/," ")
	for(i=2;i<=NF;i++) {
		if(substr($i,1,5)=="$dwh.") a=a" "substr($i,6)}
	print a
	}' file.sql

EDIT: modified some
awk '{a=$1;gsub(/[().]/," ");for(i=2;i<=NF;i++) if($i=="$dwh") a=a" "$(i+1);print a}' file.sql

Last edited by Jotne; 08-19-2013 at 04:54 AM..
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