Search string in unix and print whole matching word


 
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# 1  
Old 09-28-2011
Search string in unix and print whole matching word

Hi

I have requirement to search string starting with specific characters and print whole matching word in that string.

example

mystr="ATTRIBUTE NAME="Event Name" VALUE="Execute""

I want to search by passing "NAME=" and result should be NAME="Event Name".

i am using below command but that is printing whole line.

grep "NAME=" $mystr

Please help how to achieve above requirement.

Thanks for all your help.
Mallik.
# 2  
Old 09-28-2011
try with -o

Code:
 
echo $mystr | grep -o "NAME="

# 3  
Old 09-28-2011
I think you need to decide which style of quotes to use where, or escape the inner double quotes with \.

Code:
$ mystr="ATTRIBUTE NAME='Event Name' VALUE='Execute'"
$ echo $mystr | grep -o "NAME='[^']*'"
NAME='Event Name'

# 4  
Old 09-28-2011
This helps me a lot.. Thank you very much scottn
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