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How to grep the required part from the string?

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# 1  
Old 08-14-2013
How to grep the required part from the string?
Hi All,

I am trying to fetch the particular content from the result of grep command.

I am using

Code:
 
 
ps-ef |grep engine| awk '{print $6}'

above statement giving me

Code:
 
/opt/test/user/domain/CORPTEST/application/CacheScheduler/CacheScheduler-CacheScheduler

but I want

Code:
 
CacheScheduler-CacheScheduler

the end part of that output. Please suggest your valuable suggestions to get that required output.
# 2  
Old 08-14-2013
Code:
ps -ef | awk '/engine/{sub(/.*\//,x,$6); print $6}'

--ahamed
This User Gave Thanks to ahamed101 For This Post:
sharsour
# 3  
Old 08-14-2013
Thanks ahamed, it works like a charm.

My mistake, dint mention in the first post itself.
Last word is CacheScheduler-CacheScheduler.ear

its is giving me the exact, but wanted to know if there is way to remove the.ear also from the end?

Bunch of thanks again.
# 4  
Old 08-14-2013
Code:
ps -ef | awk '/engine/{gsub(/.*\/|\..+/,x,$6); print $6}'

--ahamed
This User Gave Thanks to ahamed101 For This Post:
sharsour
# 5  
Old 08-14-2013
@sarsour
Can you post the output of (everything it gives):
ps -ef | grep engine
# 6  
Old 08-14-2013
Hi Ahamad,

I was trying to print some of the middle value of the string like

Code:
/opt/test/user/domain/CORPTEST/application/CacheScheduler/CacheScheduler-CacheScheduler

I want CORPTEST as the output,

I was trying using SED,
Code:
sed -e '/domain/,/application/p'|ps -ef | awk '{print $12}'

but it is dipalying the whole string only.
# 7  
Old 08-14-2013
Please post this
ps -ef | grep engine
It will help us to make a complete working script.
At the moment, we do not now where in your output string data is located.
I guess at the end of the line..
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