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Help! output format from vertical to horizontal

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Top Forums Shell Programming and Scripting Help! output format from vertical to horizontal
# 15  
Old 08-09-2013
Alister - Executed the givne code, below is the output
Code:
awk ' !f{ff=$0; f=1} !x && NR%2 { if(!(f>1 && $0 ~ ff)){printf "%s\t", $0} if(f==1){f++;next}}
!(NR%2) { d=d" "$0 } $0 ~ ff {print "\n"d; x=1;d=""} END{print d} ' < $TEMP/$SCRIPT.emp > $TEMP/$SCRIPT.out8
output: 
awk: syntax error near line 1
awk: bailing out near line 1

2) Rudic - Executed the code given, below is the output
Output:
Code:
awk: syntax error near line 4
awk: bailing out near line 4

3) Ahamed,
Code:
awk ' !f{ff=$0; f=1} !x && NR%2 { if(!(f>1 && $0 ~ ff)){printf "%s\t", $0} if(f==1){f++;next}}
!(NR%2) { d=d" "$0 } $0 ~ ff {print "\n"d; x=1;d=""} END{print d} ' < $TEMP/$SCRIPT.emp 
output :
awk: syntax error near line 1
awk: bailing out near line 1

kinldy help.
Last edited by Scott; 08-09-2013 at 03:33 PM.. Reason: Code tags
# 16  
Old 08-09-2013
Please use code tags...

On Solaris, use nawk or /usr/xpg4/bin/awk
This User Gave Thanks to Scott For This Post:
rocky2013
# 17  
Old 08-09-2013
Quote:
Originally Posted by rocky2013
Alister - Executed the givne code, below is the output
Code:
awk ' !f{ff=$0; f=1} !x && NR%2 { if(!(f>1 && $0 ~ ff)){printf "%s\t", $0} if(f==1){f++;next}}
!(NR%2) { d=d" "$0 } $0 ~ ff {print "\n"d; x=1;d=""} END{print d} ' < $TEMP/$SCRIPT.emp > $TEMP/$SCRIPT.out8
output: 
awk: syntax error near line 1
awk: bailing out near line 1

That's not my code.

Mine works fine with your most recent data.
Code:
$ n=7 file=data

$ { awk 'NR==n*2 {exit} NR%2' n=$n "$file"; awk '!(NR%2)' "$file"; } | paste -d ' ' $(yes - | head -n $n)
name svc isCached isPrefetched sAccessLast sAccessTotal sRunning
COM.WM.ISEXTDC.PKGINIT:INIT init N N 2013-07-13 00:39:10 MEST 1 5
DSM_APPS_MANAGEMENT.BROKERCLIENTQUEUE_CLEANUP:CLEANUP cleanup N N 2013-08-03 16:14:19 MEST 1041 1

$ cat "$file"
name
COM.WM.ISEXTDC.PKGINIT:INIT
svc
init
isCached
N
isPrefetched
N
sAccessLast
2013-07-13 00:39:10 MEST
sAccessTotal
1
sRunning
5
name
DSM_APPS_MANAGEMENT.BROKERCLIENTQUEUE_CLEANUP:CLEANUP
svc
cleanup
isCached
N
isPrefetched
N
sAccessLast
2013-08-03 16:14:19 MEST
sAccessTotal
1041
sRunning
1

Regards,
Alister
Last edited by alister; 08-09-2013 at 03:58 PM..
# 18  
Old 08-09-2013
Scott - It worked for me

Alister - Am just checking what's wrong with the given code am unable to locate where the problem lies.

Code:
file=data
n=7
{ awk 'NR==n*2 {exit} NR%2' n=$n "$file"; awk '!(NR%2)' $file; } | paste -d ' ' $(yes - | head -n $n)
cat "$file"

Output:
Code:
awk: syntax error near line 1
awk: bailing out near line 1
awk: syntax error near line 1
awk: bailing out near line 1
name
COM.WM.ISEXTDC.PKGINIT:INIT
svc
init
isCached
N
isPrefetched
N
sAccessLast
2013-07-13 00:39:10 MEST
sAccessTotal
1
sRunning
5
name
DSM_APPS_MANAGEMENT.BROKERCLIENTQUEUE_CLEANUP:CLEANUP
svc
cleanup
isCached
N
isPrefetched
N
sAccessLast
2013-08-03 16:14:19 MEST
sAccessTotal
1041
sRunning
1

Last edited by Scott; 08-10-2013 at 02:15 AM.. Reason: Code tags
# 19  
Old 09-17-2013
Hi, Jotne, RudiC & alister
Am sorry for re-opening this thread again.
Am in need of your help to get the desired output.

Code:
name
SECURITY.SERVICES.CONFIG:GETVALUE
isPrefetched
N
sAccessLast
2013-09-13 10:50:13 MEST
sAccessTotal
1
sRunning
cHitLast
name
PUBLIC.SERVER:INVOKE
isPrefetched
N
sAccessLast
2013-09-17 15:02:05 MEST
sAccessTotal
713991
sRunning
1
name
PUBLIC.STRING:CONVERTTOSTRING
isPrefetched
N
sAccessLast
2013-09-17 03:01:54 MEST
sAccessTotal
961
sRunning
cHitLast

1) I have data which has more thand 10,000 lines with the above same pattern.
2) I was checking the value of parameter 'sRunning' which should be a numerical value ( i.e, greater than 0 )
3) Here in the above live data the parameter(sRunning) is 'cHitLast and in the second case it is 1
4) I need to print the above 4 + 1(including sRunning ) values whereever the sRunning has a value greater than 0 ( zero) example shown below
5) Need to ignore if the value of sRunning which is other than numerical.
For the above code the output should be as below
Code:
name     isPrefetched   sAccessLast      sAccessTotal  sRunning
PUBLIC.SERVER:INVOKE  N       2013-09-17 15:02:05 MEST                    713991 1

This was code given by jote and it worked for some part but latter am not able to get the desired output.
Code:
nawk ' !f{ff=$0; f=1} !x && NR%2 { if(!(f>1 && $0 ~ ff)){printf "%s\t" "\t", $0} if(f==1){f++;next}}
  !(NR%2) { d=d" "$0 } $0 ~ ff {print "\n"d; x=1;d=""} END{print d} '

Thanks a lot for your support.
Last edited by Scott; 09-17-2013 at 11:29 AM.. Reason: Use CODE tags for code blocks, not ICODE tags
# 20  
Old 09-20-2013
Hi.

Comments:

1) The post # 19 although seeming to be similar is really a different topic. If so, then it should be in a different (new) thread. That may be why there have been no responses for 2 days.

2) I strongly agree with alister in post 13 about posted data needing to be a representative sample, and not some simplified form.

3) For the question on general, the utility pr can generally handle such tasks. For example, given that the data would be on a file data1, the command on Debian GNU/Linux 5.0.8 (lenny):
Code:
pr -3 -l2 -T -s" " data1

produces
Code:
empname empid design
robert 787 consultant
empname empid design
alex 898 advocate

The idea being that columns can be specified as well as the length of a page (in this case 2 lines, no titles, no headers, no footers). See man pr for details.

Best wishes ... cheers, drl
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